I have models like this
我有这样的模特
class Book(models.Model):
title = models.CharField(max_length=254)
subtitle = models.CharField(max_length=254, null=True, blank=True)
subjects = models.ManyToManyField(Subject)
class Subject(models.Model):
name = models.CharField(max_length=255)
description = models.CharField(max_length=254, null=True, blank=True)
Now when i do
现在当我这样做
Book.objects.get_or_create(subjects=[2,4] , title='Genetics', subtitle='Theory of Genetics')
Here the value of subjects is the list of related subjects id. This gives me an error saying arguments should be string or number a TypeError
.
这里主题的价值是相关主题id的列表。这给了我一个错误,说参数应该是字符串或数字是TypeError。
How can I handle this situation with multiple subjects ?
如何处理多个科目的这种情况?
1 个解决方案
#1
1
You use the __in operator
您使用__in运算符
Book.objects.filter(subjects__in=[2,4])
It can also be used with a queryset
它也可以与查询集一起使用
Book.objects.filter(
subjects__in=Subject.objects.filter(name__contains="interesting"))
If you instead want Book with both subjects and not just any of them we can use the Q object
如果您想要同时使用Book而不是其中任何一个,我们可以使用Q对象
Book.objects.filter( Q(subject__in=[2]) & Q(subject__in=[4]) )
Note that the any of operators doest logically fit in to a get_or_create because there isnt enough information to create so you might have to split it up.
请注意,任何运算符都在逻辑上适合get_or_create,因为没有足够的信息可以创建,因此您可能需要将其拆分。
#1
1
You use the __in operator
您使用__in运算符
Book.objects.filter(subjects__in=[2,4])
It can also be used with a queryset
它也可以与查询集一起使用
Book.objects.filter(
subjects__in=Subject.objects.filter(name__contains="interesting"))
If you instead want Book with both subjects and not just any of them we can use the Q object
如果您想要同时使用Book而不是其中任何一个,我们可以使用Q对象
Book.objects.filter( Q(subject__in=[2]) & Q(subject__in=[4]) )
Note that the any of operators doest logically fit in to a get_or_create because there isnt enough information to create so you might have to split it up.
请注意,任何运算符都在逻辑上适合get_or_create,因为没有足够的信息可以创建,因此您可能需要将其拆分。