jQuery：从最小值和最大值创建变量？

I'm trying to create jquery variables using min and max values.

我正在尝试使用min和max值创建jquery变量。

To explain what i am trying to do I've created this JSFIDDLE

为了解释我想要做什么,我已经创建了这个JSFIDDLE

and this is my entire code:

这是我的整个代码:

function minMaxId(selector) {
    var min=null, max=null;
    $(".allPro").each(function() {
        var price = parseInt($(this).attr("data-price"), 10);
        if (isNaN(price)) { return; }
        if ((min===null) || (price < min)) { min = price;}
        if ((max===null) || (price > max)) { max = price;}


    });
    return [min, max];
    var maximum = max;
    var minimum = min;
}

alert(minimum);

when i run my code, i get no alert(); at all and when i look in the console, i get minimum is undifined

当我运行我的代码时,我得不到警报();在我看到控制台的时候,我得到的最小化就是不分割

could someone please let me know what i am doing wrong?

有人可以让我知道我做错了什么吗?

1 个解决方案

#1

Call function minMaxId and assign result to variable ans then use it

调用函数minMaxId并将结果赋给变量ans然后使用它

function minMaxId(selector) {
    var min=null, max=null;
    $(".allPro").each(function() {
        var price = parseInt($(this).attr("data-price"), 10);
        if (isNaN(price)) { return; }
        if ((min===null) || (price < min)) { min = price;}
        if ((max===null) || (price > max)) { max = price;}


    });

    return [min, max];
}

var result = minMaxId();
var maximum = result[1];
var minimum = result[0];

console.log(minimum);
console.log(maximum);

Example

Because in your variant function return value and you are trying assign variables after return, also you are using var - in this case this variables will be only in function scope

因为在你的variant函数返回值并且你在返回后尝试赋值变量,你也使用var - 在这种情况下这个变量只在函数范围内

#1