通过Jquery AJAX传递PHP变量

I am trying to learn the Jquery AJAX function but am struggling to work out how to pass PHP variables into my main document.

我正在尝试学习Jquery AJAX函数，但我正在努力研究如何将PHP变量传递到我的主文档中。

This is what I currently have:

这就是我目前所拥有的：

<script>
  var refreshId = setInterval(function() {
    $.ajax({
      url: "test.php",
      dataType: "json", //the return type data is jsonn
      success: function(data){ // <--- (data) is in json format
        $('#testdiv').html(data.test1);
        $('#testdiv').append(html(data.test2));
        //parse the json data
      }
    });

}, 1000);
</script>

5 个解决方案

#1

You should use json or xml format and parse it, and get the variable.

您应该使用json或xml格式并解析它，并获取变量。

<script src="jquery.js"></script>
<script>
    $.ajax({
      url: "test.php",
      dataType: "json", //the return type data is jsonn
      success: function(data){ // <--- (data) is in json format
        alert(data.test1);
        //parse the json data
      }
    });
</script>

on test.php

在test.php上

<?php

$test = array();
$test['test1'] = '1';
$test['test2'] = '2';
$test['test3'] = '3';

echo json_encode($test);
//echo nothing after this //not even html

#2

use dataType='json' in ajax option on index.php

在index.php的ajax选项中使用dataType ='json'

and on test.php use json_encode

并在test.php上使用json_encode

$ret_array= array ($test1, $test2 and $test3);
echo json_encode($ret_array);

again on index.php

再次在index.php上

now if u want to use it in your *J*S file then access via object navigation or using getJSON method

现在，如果您想在* J * S文件中使用它，则可以通过对象导航或使用getJSON方法进行访问

and if u want to use that data directly in php then use json_decode

如果你想直接在php中使用那些数据，那么使用json_decode

json_decode($ret_array,true);

References

json_encode
getJSON
json_decode

json_encode getJSON json_decode

#3

Another approach (with ajax but hidden field) would be:

另一种方法（使用ajax但隐藏字段）将是：

$.ajax({
    type: 'POST',
    url: "test.php",
    dataType: "json", //the return type data is jsonn
    success: function(data){ // <--- (data) is in json format
        $('#testdiv').html('<input type="hidden" value="' + data.test1 + '" />');
    }
    error: ajaxError,
    dataType: "html"
});

With that inside of your form you can even use your value in the next Postback without passing it directly.

使用表单内部，您甚至可以在下一个Postback中使用您的值而不直接传递它。

#4

You don't pass them into index.php, but you can add them as content that is loaded by your ajax something like this:

你没有将它们传递给index.php，但你可以将它们添加为你的ajax加载的内容，如下所示：

$test1 = '1';
$test2 = '2';
$test3 = '3';

echo $test1 . "<br/>" . $test2 . "<br/>" . $test3 . "<br/>";

#5

Unless im greatly mistaken its as simple as:

除非我非常误以为它简单如下：

<?php
  include 'test.php';
?>

To include the test.php file in index.php

在index.php中包含test.php文件

Then you can call them as if they were variables set in index.php, i would then do the following to get them into jQuery:

然后你可以调用它们就像它们是index.php中设置的变量一样，然后我会执行以下操作将它们转换为jQuery：

$("#test1") etc...

$（“＃test1”）等......

Update

更新

The problem I have is that the variables in test.php will be changing constantly, and then these need to be updated on index.php. I only set them as 1, 2 and 3 to test it out. – user683526 1 min ago

我遇到的问题是test.php中的变量会不断变化，然后需要在index.php上更新这些变量。我只将它们设置为1,2和3来测试它。 - user683526 1分钟前

In that case set them in a function and return the values.

在这种情况下，将它们设置在一个函数中并返回值。