.net SMTP发送Email实例(可带附件)

代码如下:

public static void sendEmail(string toAddress, string emailbody) 
{ 
var fromAddress = ConfigurationManager.AppSettings["EmailAddress"]; 
string fromPassword = ConfigurationManager.AppSettings["EmailPassword"].ToString(); 
const string subject = "Job Recommendation"; 
var smtp = new SmtpClient 
{ 
Host = ConfigurationManager.AppSettings["SmtpServer"].ToString(), 
Port = int.Parse(ConfigurationManager.AppSettings["SmtpPort"]), 
EnableSsl = true, 
DeliveryMethod = SmtpDeliveryMethod.Network, 
UseDefaultCredentials = false, 
Credentials = new NetworkCredential(fromAddress, fromPassword) 
}; 
using (var message = new MailMessage(fromAddress, toAddress, subject, HttpUtility.HtmlEncode(emailbody))) 
{ 
smtp.Send(message); 
} 
} 
<add key="EmailAddress" value="**********@gmail.com"/>//Email Address 
<add key="EmailPassword" value="*********"/> //Emial PWD 
<add key="SmtpServer" value="smtp.gmail.com"/> 
<add key="SmtpPort" value="587"/> 
<--带附件版本-> 
var fromAddress = "[e-mail]"; 
string fromPassword = "yj1989120"; 
const string subject = "CV"; 
var smtp = new SmtpClient 
{ 
Host = "smtp.gmail.com", 
Port = 587, 
EnableSsl = true, 
DeliveryMethod = SmtpDeliveryMethod.Network, 
UseDefaultCredentials = false, 
Credentials = new NetworkCredential(fromAddress, fromPassword) 
}; 
MailMessage email=new MailMessage(fromAddress, "[e-mail]"); 
email.Subject = "INLINE attachment TEST"; 
email.IsBodyHtml = true; 
string attachmentPath = "C:\\3.jpeg"; 
Attachment inline = new Attachment(attachmentPath); 
inline.ContentDisposition.Inline = true; 
inline.ContentDisposition.DispositionType = DispositionTypeNames.Inline; 
//inline.ContentId = "1"; 
//inline.ContentType.MediaType = "image/png"; 
inline.ContentType.Name = Path.GetFileName(attachmentPath); 
email.Attachments.Add(inline); 
email.Body = "test"; 
smtp.Send(email); 
email.Dispose(); 
//如果没有路径，用Stream 
Attachment letter = new Attachment(FileUploadLetter.FileContent, FileUploadLetter.PostedFile.ContentType); 
letter.ContentDisposition.Inline = true; 
letter.ContentDisposition.DispositionType = DispositionTypeNames.Inline; 
//inline.ContentId = "1"; 
letter.ContentType.MediaType = FileUploadLetter.PostedFile.ContentType; 
letter.ContentType.Name = Path.GetFileName(FileUploadLetter.PostedFile.FileName); 
letter.Name = Path.GetFileName(FileUploadLetter.PostedFile.FileName);