本文实例讲述了jquery获取多个checkbox的值异步提交给php的方法。分享给大家供大家参考。具体实现方法如下:
html代码:
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< tr >
< td >< input type = "checkbox" name = "uid" value="<?=$item['mtaccount_id']?>"></ td >
< td ><?=$item['mtaccount_id']?></ td >
< td ><?=$item['account_id']?></ td >
< td ><?=$item['account_name']?></ td >
< td ><?=$item['server']?></ td >
< td ><?=$item['platform']?></ td >
</ tr >
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我的是html里的数据是从数据库读出来的,在此可以理解为下面代码
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< li >< input type = "checkbox" name = "uid" value = "1" />用户1</ li >
< li >< input type = "checkbox" name = "uid" value = "2" />用户2</ li >
< li >< input type = "checkbox" name = "uid" value = "3" />用户3</ li >
< li >< input type = "checkbox" name = "uid" value = "4" />用户4</ li >
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jquery代码:
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var mt4Ids = [];
$( 'input[name=uid]' ).each( function () {
if ( this .checked) {
mt4Ids.push($( this ).val());
}
});
data = {
mt4Ids : JSON.stringify(mt4Ids)
};
var pUrl = "/a/manageUser.html" ;
$.post(pUrl, data, function (data){
if (data.state == 1){
alert(data.msg);
location.href = "/h/permission.html" ;
} else {
alert( "操作失败" );
}
}, 'json' );
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PHP代码
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$mt4Ids = ! empty ( $_POST [ 'mt4Ids' ]) ? $_POST [ 'mt4Ids' ] : false;
$stripMt4Ids = preg_replace( '/[\"\[\]]/' , '' , $mt4Ids );
$mt4IdsToArr = explode ( ',' , $stripMt4Ids );
foreach ( $mt4IdsToArr as $uid ){
permission_relation::add( $uid , $gid );
}
$data = array (
'state' => 1,
'msg' => '操作成功'
);
echo json_encode( $data );
return false;
// $gid 可忽略
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希望本文所述对大家的php程序设计有所帮助。