I have a django project in which i have a form in a div being loaded by ajax.
我有一个django项目,其中我有一个由ajax加载的div中的表单。
when I submit the form with empty fields it returns the form with the required fields shown.
当我提交带有空字段的表单时,它返回显示所需字段的表单。
when I hit submit again it redirects to the action of the form instead of reloading the form in the div and showing errors as it does the first time I submit.
当我再次点击提交时,它会重定向到表单的操作,而不是重新加载div中的表单并显示错误,就像我第一次提交时一样。
does anyone have any idea where the error might be occurring? I imagine somewhere in the ajax or view in my django project.
有没有人知道错误可能发生在哪里?我想象在我的django项目中的ajax或view中的某个地方。
here is what is returned by the second submit:
这是第二次提交返回的内容:
{"success": false, "form": "<head>\n\n</head>\n<body>\n<form action=\"/cookbook/createrecipe/\" method=\"POST\" name=\"recipeform\" id=\"createrecipeform\">\n\t<table>\n\t\t<div style='display:none'><input type='hidden' name='csrfmiddlewaretoken' value='c5ea952ee2144b377b375d91b0843c75' /></div>\n\t\t<tr><th><label for=\"id_name\">Name:</label></th><td><ul class=\"errorlist\"><li>This field is required.</li></ul><input id=\"id_name\" type=\"text\" name=\"name\" maxlength=\"200\" /></td></tr>\n<tr><th><label for=\"id_author\">Author:</label></th><td><ul class=\"errorlist\"><li>This field is required.</li></ul><input id=\"id_author\" type=\"text\" name=\"author\" maxlength=\"100\" /></td></tr>\n<tr><th><label for=\"id_picture\">Picture:</label></th><td><input type=\"file\" name=\"picture\" id=\"id_picture\" /></td></tr>\n<tr><th><label for=\"id_ingredients\">Ingredients:</label></th><td><ul class=\"errorlist\"><li>This field cannot be null.</li></ul><textarea id=\"id_ingredients\" rows=\"10\" cols=\"40\" name=\"ingredients\"></textarea></td></tr>\n<tr><th><label for=\"id_steps\">Steps:</label></th><td><ul class=\"errorlist\"><li>This field cannot be null.</li></ul><textarea id=\"id_steps\" rows=\"10\" cols=\"40\" name=\"steps\"></textarea></td></tr>\n<tr><th><label for=\"id_prep_time\">Prep time:</label></th><td><ul class=\"errorlist\"><li>This field is required.</li></ul><input type=\"text\" name=\"prep_time\" id=\"id_prep_time\" /></td></tr>\n<tr><th><label for=\"id_type\">Type:</label></th><td><ul class=\"errorlist\"><li>This field is required.</li></ul><select name=\"type\" id=\"id_type\">\n<option value=\"\" selected=\"selected\">---------</option>\n<option value=\"SW\">Sandwich</option>\n<option value=\"AP\">Appetizers</option>\n<option value=\"SD\">Sauces and Dressings</option>\n<option value=\"SS\">Soups and Salads</option>\n<option value=\"VG\">Vegetables</option>\n<option value=\"RG\">Rice, Grains and Beans</option>\n<option value=\"PA\">Pasta</option>\n<option value=\"BR\">Breakfast</option>\n<option value=\"MT\">Meat</option>\n<option value=\"SF\">Seafood</option>\n<option value=\"BP\">Bread and Pizza</option>\n<option value=\"DT\">Desserts</option>\n</select><input type=\"hidden\" name=\"reset_recipe\" id=\"id_reset_recipe\" /></td></tr>\n\t</table>\n\t<p><input type=\"submit\" value=\"Submit\"></p>\n</form>\n</body>"}
here is my ajax code:
这是我的ajax代码:
<script type="text/javascript">
$(document).ready(function(){
var form = $('form#createrecipeform');
form.submit(function(e) {
e.preventDefault();
console.log('ajax form submission function called successfully.');
//form = $(this);
console.log(form)
var serialized_form = form.serialize();
$.ajax({ type: "POST",
url: $(this).attr('action'),
data: serialized_form,
success: (function(data) {
console.log('ajax success function called successfully.');
data = $.parseJSON(data);
if (data.success) {
console.log('success');
} else {
console.log('failure');
var newForm = data.form;
form.replaceWith(newForm);
}
})
});
return false;
});
});
</script>
here is the view: (createrecipe is the action of the form and account is the page that is loading the ajax)
这里是视图:( createrecipe是表单的动作,帐号是加载ajax的页面)
def createrecipe(request):
print "entering createrecipeview"
if request.method == 'POST':
print "form is a post"
form = RecipeForm(request.POST)
print form.errors
if form.is_valid():
print "form is valid"
form = RecipeForm(initial = {'original_cookbook' : request.user.cookbooks.all()[0]})
form = form.save()
t = loader.get_template('cookbook/create_form.html')
c = RequestContext(request, {
'form': form,
})
data = {
'replace': True,
'form': t.render(c),
'success': True,
}
json = simplejson.dumps(data)
return HttpResponse(json, mimetype='text/plain')
else:
print "form is invalid"
form = RecipeForm(request.POST)
t = loader.get_template('cookbook/create_form.html')
c = RequestContext(request, {
'form':form,
})
data ={
'form': t.render(c),
'success': False,
}
json = simplejson.dumps(data)
return HttpResponse(json, mimetype='text/plain')
def account(request):
user = request.user
if request.user.is_authenticated():
cookbooks = user.cookbooks
if cookbooks.all().exists():
cookbook = cookbooks.all()[0]
form = RecipeForm(initial = {'original_cookbook' : request.user.cookbooks.all()[0]})
recipe_list = cookbook.recipes.all()
else:
raise Http404
else:
return HttpResponseRedirect('/accounts/login')
t = loader.get_template('cookbook/account.html')
c = RequestContext(request, {
'form': form,
'recipe_list': recipe_list
})
return HttpResponse(t.render(c))
here is the create_form.html template:
这是create_form.html模板:
<head>
</head>
<body>
<form action="{% url cookbook.views.createrecipe %}" method="POST" name="recipeform" id="createrecipeform">
<table>
{% csrf_token %}
{{ form.as_table }}
</table>
<p><input type="submit" value="Submit"></p>
</form>
</body>
and here is the account template that includes the create_form template:
这是包含create_form模板的帐户模板:
{% extends "cookbook/base.html" %}
{% load pagination_tags %}
{% load comments %}
<h1>{{ user }}'s Cookbook</h1>
<ul>
{% block nav-cookbooks %}
<li><a class="nav-inactive" href="/cookbooks/">Cookbooks</a></li>
{% endblock %}
{% block nav-account %}
<li><a class="nav-active" href="/account/">My Cookbook</a></li>
{% endblock %}
</ul>
{% block content %}
{% autopaginate recipe_list 6 %}
<div id="recipe_cont">
{% for recipe in recipe_list %}
<div class="recipe">
<div class="button">
<a href="{% url cookbook.views.userrecipe recipe.id %}" style="display: none;"></a>
<img src="{{ STATIC_URL }}chicknbraw.jpg" alt="" height="70" width="70" style="display:inline;" />
<h4>{{ recipe.name }}</h4>
</div>
<h5>{{ recipe.author }}</h5>
<h5>Prep Time: {{ recipe.prep_time }} minutes</h5>
<h6><a href="/addrecipe/{{ recipe.id }}">Add Recipe</a>
<a href="/removerecipe/{{ recipe.id }}">Remove Recipe</a></h6>
</div>
{% endfor %}
</div>
<div id="popupContact" class="popup">
<a id="popupContactClose" style="cursor:pointer;float:right;">x</a>
<p id="contactArea">
<h1 style="text-align:center">Create New Recipe</h1>
{% include 'cookbook/create_form.html' %}
</p>
</div>
<div id="backgroundPopup">
</div>
<div id="col2-footer">
{% paginate %}
<p id="recipe_order_text"> order by: <a href="/userbook/ordered/name">abc</a>|<a href="/userbook/ordered/date">date</a>
</div>
{% endblock %}
{% block footer %}
<a class="create" style="cursor:pointer" >Create New Recipe</a>
{% endblock %}
sorry for putting so much code but it all seems to rely upon another piece of code so I figured all relevant code would be helpful
很抱歉放了这么多代码,但它似乎都依赖于另一段代码,所以我认为所有相关代码都会有所帮助
thanks for any help you can give me
感谢你给与我的帮助
katie
1 个解决方案
#1
0
In your javascript, you're hijacking the form so that it submits via ajax, but then you're calling replaceWith on the form, so your hijacked form gets obliterated and is replaced with a new, non-hijacked form. To solve this you can either
在你的javascript中,你正在劫持表单以便它通过ajax提交,但是你在表单上调用replaceWith,所以你被劫持的表单被删除并被一个新的,未被劫持的表单替换。要解决这个问题,你也可以
1) Only replace the content of the form - this should work since you're only attaching events to the form itself and not its child elements
1)只替换表单的内容 - 这应该有效,因为您只是将事件附加到表单本身而不是其子元素
2) Write your js as a function which you can call firstly on the initial form, and subsequently on any new forms loaded via ajax.
2)将您的js编写为一个函数,您可以先在初始表单上调用,然后在通过ajax加载的任何新表单上调用。
UPDATE: for example,
更新:例如,
<script type="text/javascript">
$(document).ready(function(){
function hijack() {
var form = $('form#createrecipeform');
form.submit(function(e) {
e.preventDefault();
console.log('ajax form submission function called successfully.');
//form = $(this);
console.log(form)
var serialized_form = form.serialize();
$.ajax({ type: "POST",
url: $(this).attr('action'),
data: serialized_form,
success: (function(data) {
console.log('ajax success function called successfully.');
data = $.parseJSON(data);
if (data.success) {
console.log('success');
} else {
console.log('failure');
var newForm = data.form;
form.replaceWith(newForm);
hijack();
}
})
});
return false;
});
};
hijack();
});
</script>
#1
0
In your javascript, you're hijacking the form so that it submits via ajax, but then you're calling replaceWith on the form, so your hijacked form gets obliterated and is replaced with a new, non-hijacked form. To solve this you can either
在你的javascript中,你正在劫持表单以便它通过ajax提交,但是你在表单上调用replaceWith,所以你被劫持的表单被删除并被一个新的,未被劫持的表单替换。要解决这个问题,你也可以
1) Only replace the content of the form - this should work since you're only attaching events to the form itself and not its child elements
1)只替换表单的内容 - 这应该有效,因为您只是将事件附加到表单本身而不是其子元素
2) Write your js as a function which you can call firstly on the initial form, and subsequently on any new forms loaded via ajax.
2)将您的js编写为一个函数,您可以先在初始表单上调用,然后在通过ajax加载的任何新表单上调用。
UPDATE: for example,
更新:例如,
<script type="text/javascript">
$(document).ready(function(){
function hijack() {
var form = $('form#createrecipeform');
form.submit(function(e) {
e.preventDefault();
console.log('ajax form submission function called successfully.');
//form = $(this);
console.log(form)
var serialized_form = form.serialize();
$.ajax({ type: "POST",
url: $(this).attr('action'),
data: serialized_form,
success: (function(data) {
console.log('ajax success function called successfully.');
data = $.parseJSON(data);
if (data.success) {
console.log('success');
} else {
console.log('failure');
var newForm = data.form;
form.replaceWith(newForm);
hijack();
}
})
});
return false;
});
};
hijack();
});
</script>