Swift 3从数组中删除不存在于另一个数组中并保持顺序的对象

Array1 = [Washington, Franklin, Florida, Alaska, California, Georgia]

Array1 = [Washington，Franklin，Florida，Alaska，California，Georgia]

Array2 = [California, Washington, Georgia]

Array2 = [加利福尼亚州，华盛顿，格鲁吉亚]

I want to get

我想得到

Array1 = [Washington, California, Georgia]

Array1 = [华盛顿，加利福尼亚，格鲁吉亚]

4 个解决方案

#1

var array1 = ["Washington", "Franklin", "Florida", "Alaska", "California", "Georgia"]
var array2 = ["California", "Washington", "Georgia"]

let filterArray = array1.filter {
    array2.contains($0)
}

The filterArray is what you want

filterArray就是你想要的

#2

You can use filter for achieving desired output

您可以使用过滤器来实现所需的输出

Using filter:

使用过滤器：

let array1 = ["Washington", "Franklin", "Florida", "Alaska", "California", "Georgia"]
let array2 = ["California", "Washington", "Georgia"]

let aryCommonElements = array1.filter { array2.contains($0)}

Output:

输出：

["Washington", "California", "Georgia"]

Hope this will help you :)

希望对你有帮助：）

#3

try this

尝试这个

let filteredArray = array1.filter({Array2.contains($0)})

#4

If you want to retrieve only common elements than use:

如果您只想检索常用元素而不是使用：

In Swift 3

在Swift 3中

let Array1 = ["Washington", "Franklin", "Florida", "Alaska", "California", "Georgia"]

let Array2 = ["California", "Washington", "Georgia"]

let common = GetCommonElements(lhs: Array1, rhs: Array2)

print(common)

func GetCommonElements <T, U> (lhs: T, rhs: U) -> [T.Iterator.Element] where T: Sequence, U: Sequence, T.Iterator.Element: Equatable, T.Iterator.Element == U.Iterator.Element {
       var returnArray:[T.Iterator.Element] = []
       for lhsItem in lhs {
           for rhsItem in rhs {
               if lhsItem == rhsItem {
                  returnArray.append(lhsItem)
               }
           }
       }
       return returnArray
}

#1

var array1 = ["Washington", "Franklin", "Florida", "Alaska", "California", "Georgia"]
var array2 = ["California", "Washington", "Georgia"]

let filterArray = array1.filter {
    array2.contains($0)
}