从python中的对象列表中删除对象

In Python, how can I remove an object from array of objects? Like this:

在Python中，如何从对象数组中删除对象?是这样的:

x = object()
y = object()
array = [x,y]
# Remove x

I've tried array.remove() but it only works with a value, not a specific location in the array. I need to be able to delete the object by addressing its position(remove array[0])

我尝试过array.remove()，但它只对一个值起作用，而不是数组中的特定位置。我需要能够通过寻址对象的位置来删除它(删除数组[0])

5 个解决方案

#1

In python there are no arrays, lists are used instead. There are various ways to delete an object from a list:

在python中没有数组，而是使用列表。从列表中删除对象有多种方法:

my_list = [1,2,4,6,7]

del my_list[1] # Removes index 1 from the list
print my_list # [1,4,6,7]
my_list.remove(4) # Removes the integer 4 from the list, not the index 4
print my_list # [1,6,7]
my_list.pop(2) # Removes index 2 from the list

In your case the appropriate method to use is pop, because it takes the index to be removed:

在你的情况下，适当的方法是pop，因为它需要删除索引:

x = object()
y = object()
array = [x, y]
array.pop(0)
# Using the del statement
del array[0]

#2

del array[0]

where 0 is the index of the object in the list (there is no array in python)

其中0是列表中对象的索引(python中没有数组)

#3

If you know the array location you can can pass it into itself. If you are removing multiple items I suggest you remove them in reverse order.

如果你知道数组的位置，你可以把它传递给它自己。如果您正在删除多个项目，我建议您以相反的顺序删除它们。

#Setup array
array = [55,126,555,2,36]
#Remove 55 which is in position 0
array.remove(array[0])

#4

If you want to remove multiple object from a list. There are various ways to delete an object from a list

如果要从列表中删除多个对象。有多种方法可以从列表中删除对象

Try this code. a is list with all object, b is list object you want to remove.

试试这个代码。a是带有所有对象的列表，b是要删除的列表对象。

example :

例子:

a = [1,2,3,4,5,6]
b = [2,3]

for i in b:
   if i in a:
      a.remove(i)

print(a)

the output is [1,4,5,6] I hope, it will work for you

输出是[1,4,5,6]我希望，它对你有用。

#5

-1

if you wanna remove the last one just do your_list.pop(-1) if you wanna remove the first one your_list.pop(0) or any index you wish to remove

如果你想要删除最后一个，只需执行your_list.pop(-1)如果你想删除第一个你的_list.pop(0)或任何你想要删除的索引

#1