基于另一个数组的散列过滤数组

I am trying to filter an array of hashes based on another array. What's the best way to accomplish this? Here are the 2 brutes I've right now:

我正在尝试基于另一个数组筛选散列数组。最好的方法是什么?这是我现在的两个野兽:

x=[1,2,3]
y = [{dis:4,as:"hi"},{dis:2,as:"li"}]

1) aa = []
x.each do |a|
  qq = y.select{|k,v| k[:dis]==a}
  aa+=qq unless qq.empty?
end

2) q = []
y.each do |k,v|
  x.each do |ele|
    if k[:dis]==ele
      q << {dis: ele,as: k[:as]}
    end
  end
end

Here's the output I'm intending:

这是我想要的输出:

[{dis:2,as:"li"}]

[{说:2,:“李”}]

3 个解决方案

#1

If you want to select only the elements where the value of :dis is included in x:

如果您只想选择x中包含:dis值的元素:

y.select{|h| x.include? h[:dis]}

#2

Yes use select, nonetheless here's another way which works:

是的，使用select，尽管如此还有另一种方法:

y.each_with_object([]) { |hash,obj| obj << hash if x.include? hash[:dis] }

#3

You can delete the nonconforming elements of y in place with with .keep_if

可以使用.keep_if删除不符合要求的y元素

> y.keep_if { |h| x.include? h[:dis] }

Or reverse the logic with .delete_if:

或将逻辑与.delete_if反向:

> y.delete_if { |h| !x.include? h[:dis] }

All produce:

所有的生产:

> y
=> [{:dis=>2, :as=>"li"}]

#1