I have an array in the following format :-
我有一个以下格式的数组: -
[
{ name : "Foo",
type : "Bar"
},
{
name : "Foo",
type : "Row"
},
{
name : "Foo"
}
]
I would like to remove occurrences of "Foo" only when it doesn't have a type. Basically, there can be duplicates in the array as long as the type is different and there can not be a duplicate with no type. Any help is appreciated!
我想仅在没有类型的情况下删除“Foo”的出现。基本上,只要类型不同并且不存在没有类型的重复,数组中就可能存在重复项。任何帮助表示赞赏!
Thanks!
1 个解决方案
#1
2
I am assuming that you are working with a json_decoded array of objects. IN that case, you could run a simple array_filter() like this:
我假设您正在使用json_decoded对象数组。在这种情况下,您可以像这样运行一个简单的array_filter():
$filtered_array = array_filter($array, function($item) {
return isset($item->type);
});
#1
2
I am assuming that you are working with a json_decoded array of objects. IN that case, you could run a simple array_filter() like this:
我假设您正在使用json_decoded对象数组。在这种情况下,您可以像这样运行一个简单的array_filter():
$filtered_array = array_filter($array, function($item) {
return isset($item->type);
});