如何从数组中删除对象并推送到新数组[重复]

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How do I remove a particular element from an array in JavaScript? 69 answers

如何从JavaScript中删除数组中的特定元素? 69个答案

can someone help me with some code to splice an array and push to new array. I have an arrays

有人可以帮助我使用一些代码来拼接数组并推送到新数组。我有一个阵列

someArray = [{
  name: "Kristian",
  lines: "2,5,10"
}, {
  name: "John",
  lines: "1,19,26,96"
}, {
  name: "Kristian",
  lines: "2,58,160"
}, {
  name: "Felix",
  lines: "1,19,26,96"
}];

i want to splice where name = to Kristian and push to a new array

我想拼接name = to Kristian并推送到一个新阵列

3 个解决方案

#1

You can use .reduce() method along-with .splice():

您可以与.splice()一起使用.reduce()方法:

let data = [
  {name:"Kristian", lines:"2,5,10"}, {name:"John", lines:"1,19,26,96"},
  {name:"Kristian", lines:"2,58,160"}, {name:"Felix", lines:"1,19,26,96"}
];
  
let result = data.reduce((r, c, i, a) => {
  if(c.name = 'Kristian')
    r.push(a.splice(i, 1));
  return r;
}, []);

console.log(result);
console.log(data);

.as-console-wrapper { max-height: 100% !important; top: 0; }

#2

You can use

您可以使用

Array.prototype.filter()

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

filter()方法创建一个新数组,其中包含通过所提供函数实现的测试的所有元素。

Array.prototype.splice()

The splice() method changes the contents of an array by removing existing elements and/or adding new elements.

splice()方法通过删除现有元素和/或添加新元素来更改数组的内容。

var someArray = [{name:"Kristian", lines:"2,5,10"},{name:"John", lines:"1,19,26,96"},{name:"Kristian", lines:"2,58,160"},{name:"Felix", lines:"1,19,26,96"}];

var res = someArray.filter((p,i) => {
  if(p.name=="Kristian"){
    someArray.splice(i, 1); //remove the mached object from the original array
    return p;
  }
});

console.log(res);
console.log('----------------');
console.log(someArray);

#3

You could use a mixture of filter and map:

您可以使用过滤器和地图的混合:

const filtered = someArray.filter(obj => obj.name !== "Kristian")
const newArray = someArray.map(obj => obj.name === "Kristian")

Filtered will remove the items whilst map will create a new array with the removed items

已过滤将删除项目,而地图将创建包含已删除项目的新数组

#1