sql通过日期判断年龄函数的示例代码

时间:2022-09-24 13:35:45

定义函数:

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CREATE FUNCTION [dbo].[GetAge] 
@BirthDay nvarchar(20) --生日 
RETURNS varchar(20) 
AS
BEGIN
if(@BirthDay is NUlL or @BirthDay='')
return '';
 -- Declare the return variable here 
 DECLARE @age varchar(20) 
 DECLARE @years int
 DECLARE @months int
 DECLARE @days int
 -- Add the T-SQL statements to compute the return value here 
 set @age = ''
  
 set @years = year(GETDATE()) - year(@birthday) 
 set @months = month(GETDATE()) - month(@birthday) 
 if day(@birthday)<=day(GETDATE()) 
   set @days = day(GETDATE()) - day(@birthday) 
 else
   begin
     set @months = @months - 1 
     if MONTH(@birthday) in (1,3,5,7,8,10,12) 
       set @days = 31-day(@birthday)+day(GETDATE()) 
     else if MONTH(@birthday) in (4,6,9,11) 
       set @days = 30-day(@birthday)+day(GETDATE()) 
     else if MONTH(@birthday) = 2 
       if (year(@birthday)%4 = 0 and year(@birthday)%100 <> 0) or year(@birthday)%400 = 0 
         set @days = 29-day(@birthday)+day(GETDATE()) 
       else
         set @days = 28-day(@birthday)+day(GETDATE()) 
   end
 if @months < 0 
   begin
     set @years = @years - 1 
     set @months = @months + 12 
   end
 if @years = 0 and @months = 0 
 begin
     return convert(varchar,@days+1) + '天'
  end
 if @years > 0 
   set @age = cast(@years as varchar(5)) + '岁'
 if @years < 3 and @months > 0 and @years>-1 
 begin
   set @age = @age + cast(@months as varchar(5)) + '月'
 end
 if @years<0 
 set @age=''
 RETURN @age 
END

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sql通过日期判断年龄函数的示例代码

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原文链接:https://www.cnblogs.com/Allofus/p/15016007.html