I have two tables in MySql Company : (cname,city) works : (ename,cname,salary)
我在MySql公司有两个表:( cname,city)有效:( ename,cname,salary)
I want to display number of employees working for every company, even if that number is zero.
我想显示为每家公司工作的员工人数,即使这个数字为零。
for e.g. for
例如对于
Company :
Microsoft Bangalore
IBM NY
works :
emp1 Microsoft 10000
emp2 Microsoft 90000
output should be :
输出应该是:
Microsoft 2
IBM 0
But the following query and other similar queries print only those companies which have at least one employee :
但是以下查询和其他类似查询仅打印那些至少有一名员工的公司:
Select count(*) from works natural join company group by company.cname
If I use outer join, then the companies with zero employees will still show up in one row, so that option is out as well.
如果我使用外部联接,那么零雇员的公司仍然会出现在一行中,因此该选项也是如此。
How to do it?
怎么做?
3 个解决方案
#1
22
Classic case for a LEFT JOIN:
LEFT JOIN的经典案例:
SELECT
c.cname,
COUNT(w.ename) wcount
FROM
company c
LEFT JOIN works w ON c.cname = w.cname
GROUP BY
c.cname
#2
1
Try
尝试
Select company.cname, count(work.id) from company left join work on ....=.... group by company.cname
where you fill out the "...." parts, and change the work.id to you name
在哪里填写“....”部分,并将work.id更改为您的名字
#3
0
There is another way to do so with subquery, here is a sample from my case:
使用子查询还有另一种方法,这是我的案例中的一个示例:
select count(`order_id`) as cnt
from (
select `order_id` from `room_bookings`
where `room_id` = 3 and `day_id` = 20180201
group by `order_id`
) as b;
#1
22
Classic case for a LEFT JOIN:
LEFT JOIN的经典案例:
SELECT
c.cname,
COUNT(w.ename) wcount
FROM
company c
LEFT JOIN works w ON c.cname = w.cname
GROUP BY
c.cname
#2
1
Try
尝试
Select company.cname, count(work.id) from company left join work on ....=.... group by company.cname
where you fill out the "...." parts, and change the work.id to you name
在哪里填写“....”部分,并将work.id更改为您的名字
#3
0
There is another way to do so with subquery, here is a sample from my case:
使用子查询还有另一种方法,这是我的案例中的一个示例:
select count(`order_id`) as cnt
from (
select `order_id` from `room_bookings`
where `room_id` = 3 and `day_id` = 20180201
group by `order_id`
) as b;