使用2个分隔符“+”和“ - ”在C ++中拆分字符串

i am trying to split a string with 2 delimiters '+' and '-' in C++ using a string find a delimiter...

我试图在C ++中使用字符串分割带有2个分隔符'+'和' - '的字符串,找到分隔符...

can anyone give me a go around...

任何人都可以给我一个...

Using

str.find(delimiter)

example :

a+b-c+d

Output Required: a b c d

需要输出:a b c d

Thanks in advance

提前致谢

3 个解决方案

#1

Using std::string::substr and std::string::find

使用std :: string :: substr和std :: string :: find

    std::vector<std::string> v ; //Use vector to add the words

    std::size_t prev_pos = 0, pos;
    while ((pos = str.find_first_of("+-", prev_pos)) != std::string::npos)
    {
        if (pos > prev_pos)
            v.push_back(str.substr(prev_pos, pos-prev_pos));
        prev_pos= pos+1;
    }
    if (prev_pos< str.length())
        v.push_back(str.substr(prev_pos, std::string::npos));

Or if you use boost it will be lot easier

或者,如果你使用boost,那将会容易得多

#include <boost/algorithm/string.hpp>

std::vector<std::string> v;
boost::split(v, line, boost::is_any_of("+-"));

#2

you can do this for variable delimiters as well

您也可以为变量分隔符执行此操作

void main void()
{
   char stringToUpdate[100] , char delimeters[4];

/*
write code to assign strings and delimeter
*/
        replaceDelimeters(stringToUpdate, delimeters, ' ');
}   

void replaceDelimeters(char* myString, char* delimeters, char repChar)
{   
for (int i = 0; delimeters[i] != '\0'; i++)
    {
        for(int j=0; stringtoUpdate[j] != '\0'; j++)
        {
           if(stringtoUpdate[j] == delimeters[i])
           {
                stringtoUpdate[j] = repChar;
           }
        }
    }
}

#3

Use the function "char* strtok(char* src, const char* delimiters)" http://en.cppreference.com/w/cpp/string/byte/strtok

使用函数“char * strtok(char * src,const char * delimiters)”http://en.cppreference.com/w/cpp/string/byte/strtok

char* s = "a+b-c+d";
char* p = strtok(s, "+-");  
while (p != NULL)
{
  // do something with p
  p = strtok (NULL, "+-");
}

#1