在SpringMVC中常用的就是Controller与View。但是我们常常会需要访问静态资源,如html,js,css,image等。
默认的访问的URL都会被DispatcherServlet所拦截,但是我们希望静态资源可以直接访问。该肿么办呢?
在配置文件:web.xml可以看到:
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<!-- Processes application requests -->
< servlet >
< servlet-name >appServlet</ servlet-name >
< servlet-class >org.springframework.web.servlet.DispatcherServlet</ servlet-class >
< init-param >
< param-name >contextConfigLocation</ param-name >
< param-value >/WEB-INF/spring/appServlet/servlet-context.xml</ param-value >
</ init-param >
< load-on-startup >1</ load-on-startup >
</ servlet >
< servlet-mapping >
< servlet-name >appServlet</ servlet-name >
< url-pattern >/</ url-pattern >
</ servlet-mapping >
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静态资源访问,其实方法有多种,如:通过开放tomcat的defaultServlet,修改默认的url-parttern。
但是SpringMVC提供了更为便捷的方式处理静态资源。
解决方案:
直接在servlet-context.xml中添加资源映射。
我的开发环境:
1、Eclipse Luna SP1
2、Springsource-tool-suite 3.6.4
修改servlet-context.xml,添加resource映射即可。
servlet-context.xml的路径如下:
配置文件内容:
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<? xml version = "1.0" encoding = "UTF-8" ?>
< beans:beans xmlns = "http://www.springframework.org/schema/mvc"
xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans = "http://www.springframework.org/schema/beans"
xmlns:context = "http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
< annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
< resources mapping = "/resources/**" location = "/resources/" />
< resources mapping = "/images/**" location = "/images/" />
< resources mapping = "/js/**" location = "/js/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
< beans:bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver" >
< beans:property name = "prefix" value = "/WEB-INF/views/" />
< beans:property name = "suffix" value = ".jsp" />
</ beans:bean >
< context:component-scan base-package = "com.yank.firstapp" />
</ beans:beans >
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资源映射
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<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
< resources mapping = "/resources/**" location = "/resources/" />
< resources mapping = "/images/**" location = "/images/" />
< resources mapping = "/js/**" location = "/js/" />
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mapping:映射
location:本地资源路径,注意必须是webapp根目录下的路径。
两个*,它表示映射resources/下所有的URL,包括子路径(即接多个/)
这样我们就可以直接访问该文件夹下的静态内容了。
如:
http://localhost:8090/firstapp/images/cookie.png
http://localhost:8090/firstapp/js/jquery-1.11.2.js
效果:
陷阱:
配置的location一定要是webapp根目录下才行,如果你将资源目录,放置到webapp/WEB-INF下面的话,则就会访问失败。这个问题常常会犯。
错误方式:
WEB-INF目录作用
WEB-INF是Java的WEB应用的安全目录。所谓安全就是客户端无法访问,只有服务端可以访问的目录。
如果想在页面中直接访问其中的文件,必须通过web.xml文件对要访问的文件进行相应映射才能访问。
当然,你非要放在WEB-INF中,则必须修改resources映射,如:
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< resources mapping = "/js/**" location = "/WEB-INF/js/" />
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推荐方式:本文的目录结构为如下图所示。
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:http://www.cnblogs.com/yank/p/4477204.html