MySQL查询没有返回所需的结果

时间:2022-09-22 17:47:14

I have the query below which queries the following two tables:

我在下面的查询查询以下两个表:

Users

id | gender | interested_men | interested_wmen | name | dob      | email            | account | photoURL | timestamp
 8 | 1      |0               |1                |Jamie |1987-07-04|jampez77@gmail.com| 1       | https://.|2015-11-16 17:47:33
 9 | 0      |1               |1                |Jamima|1987-07-04|jampez87@gmail.com| 1       | https://.| 2015-11-17 14:51:38

Locations

id | uid | lat         | lng         | timestamp
8  | 9   | 53.47213437 | -2.06999151 | 2015-11-17 15:05:37
7  | 8   | 53.47213437 | -2.06999151 | 2015-11-16 17:47:33

Here is the query, I'd expect it to return the details for the user called Jamima but I don't get any results. I can't see anything wrong with the syntax so i'm not sure.

这是查询,我希望它返回名为Jamima的用户的详细信息,但我没有得到任何结果。我看不出语法有什么问题,所以我不确定。

SELECT DISTINCT 
l.uid , 
u.account , 
(
    3959 * acos
    ( 
        cos( 
            radians(53.47213437) 
        ) * 
        cos( 
            radians( lat) 
        ) * 
        cos( 
            radians( lng) - radians(-2.06999151) 
        ) + 
        sin( 
            radians(53.47213437) 
        ) * 
        sin( 
            radians( lat )
        ) 
    ) 
) distance, 
TIMESTAMPDIFF(YEAR, dob, CURDATE()) AS age 
FROM locations l 
INNER JOIN users u ON l.uid = u.id 
WHERE uid != 8 
AND gender = 0 
AND account = 1 
HAVING distance <= 200 
AND age >= 23 
AND age <= 33 
ORDER BY RAND()

I've noticed that if I remove the gender and account parts of the where clause i get the correct results through. even if though they match the where clause

我注意到,如果我删除where子句的性别和帐户部分,我会得到正确的结果。即使它们匹配where子句

2 个解决方案

#1


0  

AND gender = 0 is in your query while the table has the value of 1 set for both people

AND性别= 0在您的查询中,而表格为两个人设置了值1

#2


0  

This was an issue with the datatypes in MySQL. For some reason the fact I had gender and account set to ENUM created the issue. I simply changed the to INT and everything was fine.

这是MySQL中数据类型的问题。出于某种原因,我将性别和帐户设置为ENUM这一事实造成了问题。我只是改为INT,一切都很好。

#1


0  

AND gender = 0 is in your query while the table has the value of 1 set for both people

AND性别= 0在您的查询中,而表格为两个人设置了值1

#2


0  

This was an issue with the datatypes in MySQL. For some reason the fact I had gender and account set to ENUM created the issue. I simply changed the to INT and everything was fine.

这是MySQL中数据类型的问题。出于某种原因,我将性别和帐户设置为ENUM这一事实造成了问题。我只是改为INT,一切都很好。

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