PHP操作Mysql数据库更新数据实例

时间：2021-08-17 03:43:26

需求

  1. PHP连接数据库
  2. POST传参更新数据
  3. 查询更新后的数据

PHP连接数据库

//config.php文件内容
$database = "xx";
$dataname = "root";
$datapasswd = "xxx";
$datalocal = "localhost:3306";
//$dataport = "3306";
$con = mysqli_connect($datalocal,$dataname,$datapasswd,$database);
if(!$con){
    echo "数据库连接异常";
}
//设置查询数据库编码
mysqli_query($con,'set names utf8');

HTML表单

<html>
<center>
<p>需要修改的用户名和密码</p>
<form action="update.php" method="post">
id: <input type="text" name="id">
用户名: <input type="text" name="name">
密码: <input type="text" name="password">
<input type="submit" value="提交">
</form>
</center>
</html>

POST传参更新数据

<?php
//接收参数
$id = $_POST['id'];
$name = $_POST['name'];
$password = $_POST['password'];

//update更新需要条件
//UPDATE table_name SET field1=new-value1, field2=new-value2

$sql = "UPDATE user set name='$name',password='$password' where id=$id";

 $result = mysqli_query($con,$sql);
 if(!$result){
    echo "更新失败</br>";
 }
 else{
    echo "</hr><center>成功更新数据</center></br>";
    
 }

查询更新后的数据

$query = "select * from user";
$result1 = mysqli_query($con,$query);


//函数返回结果集中行的数量
if(mysqli_num_rows($result1)>0){
//mysqli_fetch_array以数组的形式返回，关联数组
while($row = mysqli_fetch_array($result1)){
       
    echo     
 "<center>
<table>
 <tr>
   <th>账号</th>
   <th>密码</th>
 </tr>
 <tr>
   <td>".$row['id']."</td>
   <td>".$row['name']."</td>
   <td>".$row['password']. "</td>
 </tr>
</table>
</center>";
 }      
}


//关闭数据库
 mysqli_close($con);

PHP操作Mysql数据库更新数据实例

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