This question already has an answer here:
这个问题在这里已有答案:
- Can I mix MySQL APIs in PHP? 4 answers
我可以在PHP中混合MySQL API吗? 4个答案
I'm having trouble remotly accessing a mysql database, for an android application in c#. Here is my C# script.
对于c#中的android应用程序,我无法远程访问mysql数据库。这是我的C#脚本。
void mSignUpButton_Click(object sender, EventArgs e)
{
WebClient client = new WebClient();
Uri uri = new Uri("http://hitachipickmeup.dx.am/SQLQuery.php");
NameValueCollection parameters = new NameValueCollection();
parameters.Add("Name", textName.Text);
parameters.Add("Email", txtEmail.Text);
parameters.Add("Password", txtPassword.Text);
client.UploadValuesAsync(uri, parameters);
}
And my PHP script:
我的PHP脚本:
<?php
$servername = "fdb13.awardspace.net";
$username = "2100274_pickmeup";
$password = "*************";
try
{
$conn = new PDO("mysql:host=$servername;dbname=2100274_pickmeup", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
if (isset($_POST['Name']) && isset($_POST['Email']) && isset($_POST['Password']))
{
//Get the POST variables
$mName = $_POST['Name'];
$mEmail = $_POST['Email'];
$mPassword = $_POST['Password'];
//Insert new contact into database
$query = 'INSERT INTO Contact_info (Contact_Name, Contact_Email, Contact_Password) VALUES ("$mName", "$mEmail","$mPassword")';
$result = mysqli_query($query);
}
?>
When I go to http://hitachipickmeup.dx.am/SQLQuery.php, it says "connected successfully".
当我去http://hitachipickmeup.dx.am/SQLQuery.php时,它说“连接成功”。
Phpmyadmin(database empty):http://i.stack.imgur.com/WOu6l.png
1 个解决方案
#1
1
Replace the last if statement with this:
用这个替换最后一个if语句:
if (isset($_POST['Name']) && isset($_POST['Email']) && isset($_POST['Password'])){
//Get the POST variables
$mName = $_POST['Name'];
$mEmail = $_POST['Email'];
$mPassword = $_POST['Password'];
//Insert new contact into database
$query = $conn->query('INSERT INTO Contact_info (Contact_Name, Contact_Email, Contact_Password) VALUES (:name, :email, :password)');
$query->execute([
':name' => $mName,
':email' => $mEmail,
':password' => $mPassword
]);
}
As you can see I changed it to PDO and I prepared the statement.
正如您所看到的,我将其更改为PDO并准备了声明。
As I also said in a comment you can't mix database API's, either use PDO
or MySQLi
.
正如我在评论中所说,你不能混用数据库API,要么使用PDO,要么使用MySQLi。
#1
1
Replace the last if statement with this:
用这个替换最后一个if语句:
if (isset($_POST['Name']) && isset($_POST['Email']) && isset($_POST['Password'])){
//Get the POST variables
$mName = $_POST['Name'];
$mEmail = $_POST['Email'];
$mPassword = $_POST['Password'];
//Insert new contact into database
$query = $conn->query('INSERT INTO Contact_info (Contact_Name, Contact_Email, Contact_Password) VALUES (:name, :email, :password)');
$query->execute([
':name' => $mName,
':email' => $mEmail,
':password' => $mPassword
]);
}
As you can see I changed it to PDO and I prepared the statement.
正如您所看到的,我将其更改为PDO并准备了声明。
As I also said in a comment you can't mix database API's, either use PDO
or MySQLi
.
正如我在评论中所说,你不能混用数据库API,要么使用PDO,要么使用MySQLi。