my first query returns me the value 20:
我的第一个查询返回值20:
SELECT numberofseats
from plane
where tail number in
( select flighttailnumberfk
from flight
where departuretime between '11/29/2014' and '11/30/2014' and
flightdepartureairportfk = 'jfk' and
flightarrivalairport = 'mli'
)
and my second query returns me 1:
我的第二个查询给我1:
select count(reservationseatfk)
from flight f, reservation r
where f.departuretime between '11/29/2014' and '11/30/2014' and
f.reservationflightidfk = f.flightid and r.reservationdeparturetimefk = f.departuretime
Now my problem is that I want to subtract the first query from the second query and give me the answer 19. how do i do that?
现在我的问题是我想从第二个查询中减去第一个查询并给我答案19.我该怎么做?
2 个解决方案
#1
0
You could use sub sql to subtract
你可以使用sub sql来减去
SELECT numberofseats - ( select count(reservationseatfk)
from flight f, reservation r
where f.departuretime between '11/29/2014' and '11/30/2014' and
f.reservationflightidfk = f.flightid and r.reservationdeparturetimefk = f.departuretime)
from plane
where tail number in
( select flighttailnumberfk
from flight
where departuretime between '11/29/2014' and '11/30/2014' and
flightdepartureairportfk = 'jfk' and
flightarrivalairport = 'mli'
)
#2
0
you can do it in following way:
你可以通过以下方式完成:
SELECT (query1) - (query2)
or
要么
SELECT (query1) - (query2) AS Difference
or
要么
select @result = (query1) - (query2)
#1
0
You could use sub sql to subtract
你可以使用sub sql来减去
SELECT numberofseats - ( select count(reservationseatfk)
from flight f, reservation r
where f.departuretime between '11/29/2014' and '11/30/2014' and
f.reservationflightidfk = f.flightid and r.reservationdeparturetimefk = f.departuretime)
from plane
where tail number in
( select flighttailnumberfk
from flight
where departuretime between '11/29/2014' and '11/30/2014' and
flightdepartureairportfk = 'jfk' and
flightarrivalairport = 'mli'
)
#2
0
you can do it in following way:
你可以通过以下方式完成:
SELECT (query1) - (query2)
or
要么
SELECT (query1) - (query2) AS Difference
or
要么
select @result = (query1) - (query2)