I have a string. The end is different, such as index.php?test=1&list=UL or index.php?list=UL&more=1. The one thing I'm looking for is &list=.
我有一个字符串。结尾不同，比如index.php?测试= 1列表= UL或index . php ? = UL&more = 1列表。我要找的是&list=。
How can I match it, whether it's in the middle of the string or it's at the end? So far I've got [&|\?]list=.*?([&|$]), but the ([&|$]) part doesn't actually work; I'm trying to use that to match either & or the end of the string, but the end of the string part doesn't work, so this pattern matches the second example but not the first.
如何匹配它，不管是在弦的中间还是在末端?到目前为止我有=[& | \ ?]列表。* ?((& | $)),但((& | $))的部分不工作;我试着用它来匹配&或字符串的结尾，但是字符串部分的结尾不起作用，所以这个模式匹配第二个例子，但不匹配第一个。
1 个解决方案
#1
36
Use:
使用:
/(&|\?)list=.*?(&|$)/
Note that when you use a bracket expression, every character within it (with some exceptions) is going to be interpreted literally. In other words, [&|$] matches the characters &, |, and $.
注意，当您使用方括号表达式时，其中的每个字符(除了某些例外)都将按字面意义进行解释。换句话说，[&|$]匹配字符&、|和$。
#1
36
Use:
使用:
/(&|\?)list=.*?(&|$)/
Note that when you use a bracket expression, every character within it (with some exceptions) is going to be interpreted literally. In other words, [&|$] matches the characters &, |, and $.
注意，当您使用方括号表达式时，其中的每个字符(除了某些例外)都将按字面意义进行解释。换句话说，[&|$]匹配字符&、|和$。