sqlite> SELECT * FROM RawResponseTimes WHERE CreationTime <= 2011-06-14 17:17:23;
Error: near ":17": syntax error
Everything appears to be fine but it isn't happy with the hour 17, what gives?
一切似乎都很好,但却不满意17时,是什么给予?
Using SQLite.
使用SQLite。
3 个解决方案
#1
22
Keep data value in single quotes...
将数据值保持在单引号中……
sqlite> SELECT * FROM RawResponseTimes WHERE CreationTime <= '2011-06-14 17:17:23';
sqlite>从CreationTime <= '2011-06-14 17:17:23'的RawResponseTimes中选择*;
#2
28
Looks like you are missing '
s from your date.
看来你错过了约会的机会。
SELECT * FROM RawResponseTimes WHERE CreationTime <= '2011-06-14 17:17:23';
选择* FROM RawResponseTimes,其中CreationTime <= '2011-06-14 17:17:23';
#3
0
SELECT * FROM RawResponseTimes WHERE CreationTime <= CONVERT(DATETIME, '2011-06-14 17:17:23');
#1
22
Keep data value in single quotes...
将数据值保持在单引号中……
sqlite> SELECT * FROM RawResponseTimes WHERE CreationTime <= '2011-06-14 17:17:23';
sqlite>从CreationTime <= '2011-06-14 17:17:23'的RawResponseTimes中选择*;
#2
28
Looks like you are missing '
s from your date.
看来你错过了约会的机会。
SELECT * FROM RawResponseTimes WHERE CreationTime <= '2011-06-14 17:17:23';
选择* FROM RawResponseTimes,其中CreationTime <= '2011-06-14 17:17:23';
#3
0
SELECT * FROM RawResponseTimes WHERE CreationTime <= CONVERT(DATETIME, '2011-06-14 17:17:23');