First time sed'er, so be gentle.
第一次见面，所以要温柔。
I have the following text file, 'test_file':
我有以下文本文件'test_file':
<Tag1>not </Tag1><Tag2>working</Tag2>
I want to extract the text in between <Tag2> using sed regex, there may be other occurrences of <Tag2> and I would like to extract those also.
我想使用sed regex在
So far I have this sed based regex:
到目前为止，我有这个基于sed的regex:
cat test_file | grep -i "Tag2"| sed 's/<[^>]*[>]//g'
which gives the output:
使输出:
not working
Anyone any idea how to get this working?
有人知道怎么让它工作吗?
4 个解决方案
#1
4
As another poster said, sed may not be the best tool for this job. You may want to use something built for XML parsing, or even a simple scripting language, such as perl.
正如另一个海报所言，sed可能不是这项工作的最佳工具。您可能希望使用为XML解析而构建的东西，甚至是简单的脚本语言，比如perl。
The problem with your try, is that you aren't analyzing the string properly.
你尝试的问题是，你没有正确地分析字符串。
cat test_file is good - it prints out the contents of the file to stdout.
cat test_file是好的——它将文件的内容打印出来给stdout。
grep -i "Tag2" is ok - it prints out only lines with "Tag2" in them. This may not be exactly what you want. Bear in mind that it will print the whole line, not just the <Tag2> part, so you will still have to search out that part later.
grep -i“Tag2”没有问题——它只打印带有“Tag2”的行。这可能不是你想要的。请记住，它将打印整个行，而不仅仅是
sed 's/<[^>]*[>]//g' isn't what you want - it simply removes the tags, including <Tag1> and <Tag2>.
sed的s / & lt;[^祝辞]*[在]/ / g的不是你想要的东西——它只是删除标签,包括 <标签1> 和 <标签2> 。
You can try something like:
你可以试试:
cat tmp.tmp | grep -i tag2 | sed 's/.*<Tag2>\(.*\)<\/Tag2>.*/\1/'
This will produce
这将产生
working
but it will only work for one tag pair.
但它只适用于一对标签。
#2
4
For your nice, friendly example, you could use
对于您友好的示例，您可以使用
sed -e 's/^.*<Tag2>//' -e 's!</Tag2>.*!!' test-file
but the XML out there is cruel and uncaring. You're asking for serious trouble using regular expressions to scrape XML.
但是XML的存在是残酷和冷漠的。使用正则表达式获取XML会带来严重的麻烦。
#3
0
you can use gawk, eg
你可以用呆瓜(如)
$ cat file
<Tag1>not </Tag1><Tag2>working here</Tag2>
<Tag1>not </Tag1><Tag2>
working
</Tag2>
$ awk -vRS="</Tag2>" '/<Tag2>/{gsub(/.*<Tag2>/,"");print}' file
working here
working
#4
0
awk -F"Tag2" '{print $2}' test_1 | sed 's/[^a-zA-Z]//g'
#1
4
As another poster said, sed may not be the best tool for this job. You may want to use something built for XML parsing, or even a simple scripting language, such as perl.
正如另一个海报所言，sed可能不是这项工作的最佳工具。您可能希望使用为XML解析而构建的东西，甚至是简单的脚本语言，比如perl。
The problem with your try, is that you aren't analyzing the string properly.
你尝试的问题是，你没有正确地分析字符串。
cat test_file is good - it prints out the contents of the file to stdout.
cat test_file是好的——它将文件的内容打印出来给stdout。
grep -i "Tag2" is ok - it prints out only lines with "Tag2" in them. This may not be exactly what you want. Bear in mind that it will print the whole line, not just the <Tag2> part, so you will still have to search out that part later.
grep -i“Tag2”没有问题——它只打印带有“Tag2”的行。这可能不是你想要的。请记住，它将打印整个行，而不仅仅是
sed 's/<[^>]*[>]//g' isn't what you want - it simply removes the tags, including <Tag1> and <Tag2>.
sed的s / & lt;[^祝辞]*[在]/ / g的不是你想要的东西——它只是删除标签,包括 <标签1> 和 <标签2> 。
You can try something like:
你可以试试:
cat tmp.tmp | grep -i tag2 | sed 's/.*<Tag2>\(.*\)<\/Tag2>.*/\1/'
This will produce
这将产生
working
but it will only work for one tag pair.
但它只适用于一对标签。
#2
4
For your nice, friendly example, you could use
对于您友好的示例，您可以使用
sed -e 's/^.*<Tag2>//' -e 's!</Tag2>.*!!' test-file
but the XML out there is cruel and uncaring. You're asking for serious trouble using regular expressions to scrape XML.
但是XML的存在是残酷和冷漠的。使用正则表达式获取XML会带来严重的麻烦。
#3
0
you can use gawk, eg
你可以用呆瓜(如)
$ cat file
<Tag1>not </Tag1><Tag2>working here</Tag2>
<Tag1>not </Tag1><Tag2>
working
</Tag2>
$ awk -vRS="</Tag2>" '/<Tag2>/{gsub(/.*<Tag2>/,"");print}' file
working here
working
#4
0
awk -F"Tag2" '{print $2}' test_1 | sed 's/[^a-zA-Z]//g'