I want to extract patterns that appert multiple times in a string. For example,getting two an array lay of two digit integers from a string
我想在字符串中多次提取appert的模式。例如，从字符串中获取两个数组的两位数整数
wahoaet56oihaioet67jlkiwoeah67ladohwae45lkaowearho56
wahoaet56oihaioet67jlkiwoeah67ladohwae45lkaowearho56
I thought result="wahoaet56oihaioet67jlkiwoeah67ladohwae45lkaowearho56".match(/([0-9]{2})/) should give a MatchData object whose captures method should give me an array of matched patters, but it seems there is something I am missing. It only give back the first find. Even using $1,$2,$3 etc doesn't work. I am using ruby
我认为result =“wahoaet56oihaioet67jlkiwoeah67ladohwae45lkaowearho56”.match（/（[0-9] {2}）/）应该给出一个MatchData对象，其捕获方法应该给我一个匹配模式的数组，但似乎有一些我缺少的东西。它只回馈第一个发现。即使使用1美元，2美元，3美元等也行不通。我正在使用红宝石
How should I do this?
我该怎么做？
2 个解决方案
#1
10
string.scan(/regex/)
should do it
应该这样做
#2
5
scan does what you want:
扫描做你想要的：
str = "wahoaet56oihaioet67jlkiwoeah67ladohwae45lkaowearho56"
p str.scan(/\d+/) #=> ["56", "67", "67", "45", "56"]
#1
10
string.scan(/regex/)
should do it
应该这样做
#2
5
scan does what you want:
扫描做你想要的：
str = "wahoaet56oihaioet67jlkiwoeah67ladohwae45lkaowearho56"
p str.scan(/\d+/) #=> ["56", "67", "67", "45", "56"]