I have some input data such as
我有一些输入数据,如
some string with 'hello' inside 'and inside'
一些字符串'hello'在'内部'和'内部'
How can I write a regex so that the quoted text (no matter how many times it is repeated) is returned (all of the occurrences).
如何编写正则表达式,以便返回引用的文本(无论重复多少次)(所有出现的次数)。
I have a code that returns a single quotes, but I want to make it so that it returns multiple occurances:
我有一个返回单引号的代码,但我想让它返回多个出现:
String mydata = "some string with 'hello' inside 'and inside'";
Pattern pattern = Pattern.compile("'(.*?)+'");
Matcher matcher = pattern.matcher(mydata);
while (matcher.find())
{
System.out.println(matcher.group());
}
3 个解决方案
#1
3
Find all occurences for me:
找到所有出现的事情:
String mydata = "some '' string with 'hello' inside 'and inside'";
Pattern pattern = Pattern.compile("'[^']*'");
Matcher matcher = pattern.matcher(mydata);
while(matcher.find())
{
System.out.println(matcher.group());
}
Output:
输出:
'' 'hello' 'and inside'
Pattern desciption:
模式描述:
' // start quoting text [^'] // all characters not single quote * // 0 or infinite count of not quote characters ' // end quote
#2
0
I believe this should fit your requirements:
我相信这应该符合您的要求:
\'\w+\'
#3
0
\'.*?'
is the regex you are looking for.
\ '*?'是你正在寻找的正则表达式。
#1
3
Find all occurences for me:
找到所有出现的事情:
String mydata = "some '' string with 'hello' inside 'and inside'";
Pattern pattern = Pattern.compile("'[^']*'");
Matcher matcher = pattern.matcher(mydata);
while(matcher.find())
{
System.out.println(matcher.group());
}
Output:
输出:
'' 'hello' 'and inside'
Pattern desciption:
模式描述:
' // start quoting text [^'] // all characters not single quote * // 0 or infinite count of not quote characters ' // end quote
#2
0
I believe this should fit your requirements:
我相信这应该符合您的要求:
\'\w+\'
#3
0
\'.*?'
is the regex you are looking for.
\ '*?'是你正在寻找的正则表达式。