本文实例为大家分享了C语言实现Floyd算法的具体代码,供大家参考,具体内容如下
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#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
#define NUM 4
typedef struct MGraph /* 邻接表存储结构 */
{
int edges[NUM][NUM];
int n,e;
} MGraph;
MGraph *build_mgraph();
void Floyd(MGraph *mgraph);
void Ppath( int path[][NUM], int i, int j);
void Dispath( int A[][NUM], int path[][NUM], int n);
int main( void )
{
MGraph *mgraph;
printf ( "\n*************************************************************\n" );
printf ( "该图的矩阵表示为:\n" );
mgraph=build_mgraph();
printf ( "\n*************************************************************\n" );
printf ( "各顶点间最短路径为:\n" );
Floyd(mgraph);
printf ( "\n*************************************************************\n" );
return 0;
}
MGraph *build_mgraph()
{
int i,j;
int num_e=0;
MGraph *mgraph=(MGraph *) malloc ( sizeof (MGraph));
int matrix[NUM][NUM]={{0,5,INT_MAX,7},
{INT_MAX,0,4,2},
{3,3,0,2},
{INT_MAX,INT_MAX,1,0}};
for (i=0;i<NUM;i++)
{
for (j=0;j<NUM;j++)
{
mgraph->edges[i][j]=matrix[i][j];
if (matrix[i][j]!=0 && matrix[i][j]!=INT_MAX)
num_e++;
}
}
mgraph->n=NUM;
mgraph->e=num_e;
printf ( "node=%d;edges=%d\n" ,mgraph->n,mgraph->e);
for (i=0;i<NUM;i++)
{
for (j=0;j<NUM;j++)
{
if (mgraph->edges[i][j]!=INT_MAX)
printf ( "%3d" ,mgraph->edges[i][j]);
else
printf ( "%3c" , '&' );
}
printf ( "\n" );
}
return mgraph;
}
void Floyd(MGraph *mgraph)
{
int A[NUM][NUM],path[NUM][NUM];
int i,j,k;
for (i=0;i<mgraph->n;i++)
{
for (j=0;j<mgraph->n;j++)
{
A[i][j]=mgraph->edges[i][j];
path[i][j]=-1;
}
}
for (k=0;k<mgraph->n;k++)
{
for (i=0;i<mgraph->n;i++)
{
for (j=0;j<mgraph->n;j++)
{
if (A[i][k]!=INT_MAX && A[k][j]!=INT_MAX && A[i][j]>A[i][k]+A[k][j])
{
A[i][j]=A[i][k]+A[k][j];
path[i][j]=k;
}
}
}
}
Dispath(A,path,mgraph->n);
}
void Ppath( int path[][NUM], int i, int j)
{
int k;
k=path[i][j];
if (k==-1)
return ;
Ppath(path,i,k);
printf ( "%d," ,k);
Ppath(path,k,j);
}
void Dispath( int A[][NUM], int path[][NUM], int n)
{
int i,j;
for (i=0;i<n;i++)
{
for (j=0;j<n;j++)
{
if (A[i][j]==INT_MAX)
printf ( "%d-%d have no path" ,i,j);
printf ( "%d-%d-%d: " ,i,j,A[i][j]);
printf ( "%d," ,i);
Ppath(path,i,j);
printf ( "%d\n" ,j);
}
}
}
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以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持服务器之家。
原文链接:http://blog.csdn.net/xiaowang627/article/details/51592623