Here's what I'm trying to accomplish:
这是我想要完成的事情:
- A project manager fills out a Google Form. It spits the result to a spreadsheet, and I want to manipulate that data.
- The first question/cell is what social media the product is using, with a multiple choice checkbox.
- If someone checks off Facebook and Twitter, the cell returns "Facebook, Twitter" and I'm having trouble searching the cell for "Twitter" since it's not first.
项目经理填写Google表格。它将结果吐出到电子表格中,我想操纵该数据。
第一个问题/单元格是产品使用的社交媒体,带有多选复选框。
如果有人检查Facebook和Twitter,该单元格会返回“Facebook,Twitter”,而我在搜索单元格时遇到“Twitter”,因为它不是第一个。
Here's what I have so far:
这是我到目前为止所拥有的:
function testplan() {
var mainsheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Sheet1");
var testplan = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("TestPlan");
var socialData = mainsheet.getRange(3, 3).getValues();
var socialDataText = socialData.length;
var fbSocial = "Facebook";
var twitSocial = "Twitter";
for (var i = 0; i < socialDataText; i++) {
if (socialData[i][0] == fbSocial) {
testplan.getRange("A15").setValue("User can log into the app with Facebook.");
testplan.getRange("A16").setValue("User can share content from the app with Facebook.");
} {
return 0;
};
};
for (var i = 0; i < socialDataText; i++) {
if (socialData[i][0] == twitSocial) {;
testplan.getRange("A17").setValue("User can log into the app with Twitter.");
testplan.getRange("A18").setValue("User can share content from the app with Twitter.");
} {
return 0;
};
};
The first command to look for "Facebook" works, because it's the first bit of text. But anything after it isn't able to be found. I've searched a lot and have found things that are close, but nothing that works the way I'm expecting it to. It's probably a command or something really obvious that I'm not seeing.
寻找“Facebook”的第一个命令有效,因为它是第一个文本。但是之后的任何事情都无法找到。我经常搜索并发现了很接近的东西,但是没有任何东西能像我期待的那样发挥作用。这可能是一个命令,或者我没有看到的非常明显的事情。
1 个解决方案
#1
try
function testplan() {
var mainsheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Sheet1");
var testplan = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("TestPlan");
var socialData = mainsheet.getRange(3, 3).getValues();
var socialDataText = socialData.length;
var fbSocial = "Facebook";
var twitSocial = "Twitter";
for (var i = 0; i < socialDataText; i++) {
if (socialData[i][0].indexOf(fbSocial) > -1) {
testplan.getRange("A15").setValue("User can log into the app with Facebook.");
testplan.getRange("A16").setValue("User can share content from the app with Facebook.");
};
if (socialData[i][0].indexOf(twitSocial) > -1) {;
testplan.getRange("A17").setValue("User can log into the app with Twitter.");
testplan.getRange("A18").setValue("User can share content from the app with Twitter.");
};
};
};
for simplicity
#1
try
function testplan() {
var mainsheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Sheet1");
var testplan = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("TestPlan");
var socialData = mainsheet.getRange(3, 3).getValues();
var socialDataText = socialData.length;
var fbSocial = "Facebook";
var twitSocial = "Twitter";
for (var i = 0; i < socialDataText; i++) {
if (socialData[i][0].indexOf(fbSocial) > -1) {
testplan.getRange("A15").setValue("User can log into the app with Facebook.");
testplan.getRange("A16").setValue("User can share content from the app with Facebook.");
};
if (socialData[i][0].indexOf(twitSocial) > -1) {;
testplan.getRange("A17").setValue("User can log into the app with Twitter.");
testplan.getRange("A18").setValue("User can share content from the app with Twitter.");
};
};
};
for simplicity