how can i get a string after a specific substring .
如何在特定子字符串之后获得字符串。
For example I want to get the string after "world" in my_string="hello python world , i'm a beginner "
例如，我想在my_string="hello python世界"中获得"world"后的字符串，我是初学者。
6 个解决方案
#1
214
The easiest way is probably just to split on your target word
最简单的方法可能就是将你的目标词拆分
my_string="hello python world , i'm a beginner "
print my_string.split("world",1)[1]
split takes the word(or character) to split on and optionally a limit to the number of splits.
split将单词(或字符)分隔开，并可以选择对分割的数量进行限制。
In this example split on "world" and limit it to only one split.
在这个例子中，在“世界”上分割，并将它限制为一个分割。
#2
33
s1 = "hello python world , i'm a beginner "
s2 = "world"
print s1[s1.index(s2) + len(s2):]
If you want to deal with the case where s2 is not present in s1, then use s1.find(s2) as opposed to index. If the return value of that call is -1, then s2 is not in s1.
如果您想处理s2在s1中不存在的情况，那么请使用s1.find(s2)，而不是索引。如果调用的返回值是-1，则s2不在s1中。
#3
30
I'm surprised nobody mentioned partition.
我很惊讶没有人提到分区。
def substring_after(s, delim):
return s.partition(delim)[2]
IMHO, this solution is more readable than @arshajii's. Other than that, I think @arshajii's is the best for being the fastest -- it does not create any unnecessary copies/substrings.
IMHO，这个解决方案比@arshajii的更具可读性。除此之外，我认为@arshajii是最快的——它不会创建任何不必要的拷贝/子字符串。
#4
12
If you want to do this using regex, you could simply use a non-capturing group, to get the word "world" and then grab everything after, like so
如果你想用正则表达式来做这个，你可以简单地使用一个非捕获组，来得到单词“world”，然后再抓取所有东西，就像这样。
(?:world).*
The example string is tested here
这里测试示例字符串
#5
2
It's an old question but i faced a very same scenario, i need to split a string using as demiliter the word "low" the problem for me was that i have in the same string the word below and lower.
这是一个老问题，但我遇到了一个非常相同的情况，我需要用"low"这个词来分割一个字符串对我来说，问题是我有一个相同的字符串下面的和下面的。
I solved it using the re module this way
我用re模块解决了这个问题
import re
string = '...below...as higher prices mean lower demand to be expected. Generally, a high reading is seen as negative (or bearish), while a low reading is seen as positive (or bullish) for the Korean Won.'
use re.split with regex to match the exact word
使用re.split与regex进行匹配
stringafterword = re.split('\\blow\\b',string)[-1]
print(stringafterword)
' reading is seen as positive (or bullish) for the Korean Won.'
the generic code is:
泛型代码是:
re.split('\\bTHE_WORD_YOU_WANT\\b',string)[-1]
Hope this can help someone!
希望这能对别人有所帮助!
#6
0
You can use this package called "substring". Just type "pip install substring". You can get the substring by just mentioning the start and end characters/indices.
您可以使用这个名为“substring”的包。只需输入“pip安装子字符串”。只要提到开始和结束字符/索引，就可以获得子字符串。
For example:
例如:
import substring
s = substring.substringByChar("abcdefghijklmnop", startChar="d", endChar="n")
print(s)
Output:
输出:
s = defghijklmn
#1
214
The easiest way is probably just to split on your target word
最简单的方法可能就是将你的目标词拆分
my_string="hello python world , i'm a beginner "
print my_string.split("world",1)[1]
split takes the word(or character) to split on and optionally a limit to the number of splits.
split将单词(或字符)分隔开，并可以选择对分割的数量进行限制。
In this example split on "world" and limit it to only one split.
在这个例子中，在“世界”上分割，并将它限制为一个分割。
#2
33
s1 = "hello python world , i'm a beginner "
s2 = "world"
print s1[s1.index(s2) + len(s2):]
If you want to deal with the case where s2 is not present in s1, then use s1.find(s2) as opposed to index. If the return value of that call is -1, then s2 is not in s1.
如果您想处理s2在s1中不存在的情况，那么请使用s1.find(s2)，而不是索引。如果调用的返回值是-1，则s2不在s1中。
#3
30
I'm surprised nobody mentioned partition.
我很惊讶没有人提到分区。
def substring_after(s, delim):
return s.partition(delim)[2]
IMHO, this solution is more readable than @arshajii's. Other than that, I think @arshajii's is the best for being the fastest -- it does not create any unnecessary copies/substrings.
IMHO，这个解决方案比@arshajii的更具可读性。除此之外，我认为@arshajii是最快的——它不会创建任何不必要的拷贝/子字符串。
#4
12
If you want to do this using regex, you could simply use a non-capturing group, to get the word "world" and then grab everything after, like so
如果你想用正则表达式来做这个，你可以简单地使用一个非捕获组，来得到单词“world”，然后再抓取所有东西，就像这样。
(?:world).*
The example string is tested here
这里测试示例字符串
#5
2
It's an old question but i faced a very same scenario, i need to split a string using as demiliter the word "low" the problem for me was that i have in the same string the word below and lower.
这是一个老问题，但我遇到了一个非常相同的情况，我需要用"low"这个词来分割一个字符串对我来说，问题是我有一个相同的字符串下面的和下面的。
I solved it using the re module this way
我用re模块解决了这个问题
import re
string = '...below...as higher prices mean lower demand to be expected. Generally, a high reading is seen as negative (or bearish), while a low reading is seen as positive (or bullish) for the Korean Won.'
use re.split with regex to match the exact word
使用re.split与regex进行匹配
stringafterword = re.split('\\blow\\b',string)[-1]
print(stringafterword)
' reading is seen as positive (or bullish) for the Korean Won.'
the generic code is:
泛型代码是:
re.split('\\bTHE_WORD_YOU_WANT\\b',string)[-1]
Hope this can help someone!
希望这能对别人有所帮助!
#6
0
You can use this package called "substring". Just type "pip install substring". You can get the substring by just mentioning the start and end characters/indices.
您可以使用这个名为“substring”的包。只需输入“pip安装子字符串”。只要提到开始和结束字符/索引，就可以获得子字符串。
For example:
例如:
import substring
s = substring.substringByChar("abcdefghijklmnop", startChar="d", endChar="n")
print(s)
Output:
输出: