如何匹配字符串，直到不跟随另一个特定字符的字符的第一个实例

相关问题：如何在不遵循特定字符（？）时使用正则表达式匹配字符（'）？

I'm parsing a log using regex (PHP PCRE library), and trying to extract a URL from it. The URL is encapsulated in double quotes ", but some of the requests also include a double quote ". For example:

我正在使用正则表达式（PHP PCRE库）解析日志，并尝试从中提取URL。 URL用双引号“封装，但有些请求还包含双引号”。例如：

"https://www.amh.net.au/online/dbSearch.php?t=all&q=\"Rosuvastatin\""

My first pattern was basically:

我的第一个模式基本上是：

#\"([^\"]*)\"#

This worked well, until I reached one of the entries as above, and it truncated the match so all I got was:

这很有效，直到我达到上面的一个条目，它截断了匹配，所以我得到的是：

https://www.amh.net.au/online/dbSearch.php?t=all&q=\

After digging around, and rediscovering the cheatsheets for regex at http://addedbytes.com and also some more useful information at http://www.regular-expressions.info/lookaround.html I have now tried the following look-behind:

在浏览了http://addedbytes.com并在http://www.regular-expressions.info/lookaround.html上重新发现了正则表达式的cheatsheets以及更多有用的信息后，我现在尝试了以下的后视：

#"([(?<!\\)"]*)"#

But, now all I get is "" and then an empty string

但是，现在我得到的只是“”然后是一个空字符串

2 个解决方案

#1

The URLs in the logs would be URL-encoded. As such, the following pattern should work:

日志中的URL将进行URL编码。因此，以下模式应该起作用：

#\"([^ ]*)\"#

#2

You placed your lookbehind INSIDE your group ([]), so it's not interpreted as such, but rather just you say you only want those individual characters.
Basically, I think you'd like something like this:

你把你的lookbehind放在你的组（[]）中，所以它不是这样解释的，而只是你说你只想要那些单独的角色。基本上，我认为你喜欢这样的东西：

#"(?:[^"]|(?<=\\)")"#

Though you should be aware that you'd be trolled by \\" for example.

虽然你应该意识到你会被\\“所控制。

#1