I want to access all the data of a model in one of its views, which I made and called searching.php
. I wrote an action in the business
controller which is like this:
我想在其中一个视图中访问模型的所有数据,我创建并称之为searching.php。我在业务控制器中写了一个动作,如下所示:
public function actionSearching()
{
// using the default layout 'protected/views/layouts/main.php'
$this->layout='//layouts/main';
$this->render('searching');
}
In the view of business/searching
I want to access all the data of a model (Business). This includes business_name, business_description etc. But when I run this code I get error 500, Undefined variable: model
.
在业务/搜索的视图中,我想访问模型(业务)的所有数据。这包括business_name,business_description等。但是当我运行此代码时,我得到错误500,未定义变量:model。
Here is my searching.php file code:
这是我的search.php文件代码:
foreach ($model as $ma)
{
echo $ma->business_name;
}
I am a yii bie, I know very little about yii. How can I access all the data in a view?
我是个傻瓜,我对yii知之甚少。如何访问视图中的所有数据?
1 个解决方案
#1
1
You need to pass your models in the view
when you call render()
.
调用render()时,需要在视图中传递模型。
In your controller:
在你的控制器中:
public function actionSearching() {
$models = Business::model()->findAll();
$this->layout='//layouts/main';
$this->render('searching', array(
'models'=>$models,
));
}
In your view:
在你看来:
foreach($models as $model) {
echo $model->business_name;
}
#1
1
You need to pass your models in the view
when you call render()
.
调用render()时,需要在视图中传递模型。
In your controller:
在你的控制器中:
public function actionSearching() {
$models = Business::model()->findAll();
$this->layout='//layouts/main';
$this->render('searching', array(
'models'=>$models,
));
}
In your view:
在你看来:
foreach($models as $model) {
echo $model->business_name;
}