一、
1.新建表 test
id varchar2(20)
name varchar2(20)
addr varchar2(50)
score number
create table test
(id varchar2(20),
name varchar2(20),
addr varchar2(50),
score number
)
2.给id增加主键约束
alter table test add constraint pk_id primary key(id)
3.查询出分数大于60分的人员，并按分数降序进行排列
select * from test where score>60 order by score desc
4.新增数据 001 zhangsan shenzhen 80
insert into test(id,name,addr,score) values (‘001‘,‘zhansgan‘,‘shenzhen‘,‘80‘)
6. 将zhangsan的分数修改成60
update test set score=60 where name=‘zhangsan‘
7.删除zhangsan的信息
delete from test where name=‘zhangsan‘
二、
Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
问题：
1、查询平均成绩大于60分的同学的学号和平均成绩； avg
select s#,avg(score) from sc where (select avg(score) from sc)>60 group by s# ;
select s#,avg(score) from sc where group by s# having avg(score)>60;
2、查询所有同学的学号、姓名、选课数、总成绩；
select Student.s#,sname,count(C#),sum(score) from Student inner join sc on Student.s#=sc.s# group by Student.s#,sname
4、查询没学过“叶平”老师课的同学的学号、姓名；
select S#,Sname from Student where s# in (select S# from sc where c# not in (select c# from Course where T#=(select T# from teacher where Tname=‘叶平‘ ))
5、查询所有课程成绩小于60分的同学的学号、姓名；
select S#,Sname from Student where s# not in (select S# from sc where score>60)
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向student表插入记录的INSERT语句如下：
INSERT INTO student VALUES( 901,‘张老大‘, ‘男‘,1985,‘计算机系‘, ‘北京市海淀区‘);
INSERT INTO student VALUES( 902,‘张老二‘, ‘男‘,1986,‘中文系‘, ‘北京市昌平区‘);
INSERT INTO student VALUES( 903,‘张三‘, ‘女‘,1990,‘中文系‘, ‘湖南省永州市‘);
INSERT INTO student VALUES( 904,‘李四‘, ‘男‘,1990,‘英语系‘, ‘辽宁省阜新市‘);
INSERT INTO student VALUES( 905,‘王五‘, ‘女‘,1991,‘英语系‘, ‘福建省厦门市‘);
INSERT INTO student VALUES( 906,‘王六‘, ‘男‘,1988,‘计算机系‘, ‘湖南省衡阳市‘);
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6.从student表中查询年龄18~22岁的学生信息
SELECT id,name,sex,2010-birth AS age,department,address FROM student WHERE 2010-birth>=18 AND 2010-birth<=22; （其实没有age，直接计算今年年份-出生birth）
SELECT id,name,sex,2013-birth AS age,department,address FROM student WHERE 2013-birth BETWEEN 18 AND 22;
7.从student表中查询每个院系有多少人
SELECT department, COUNT(id) FROM student GROUP BY department;
8.从score表中查询每个科目的最高分
SELECT c_name,MAX(grade) FROM score GROUP BY c_name;
9.查询李四的考试科目（c_name）和考试成绩（grade）
SELECT c_name, grade FROM score WHERE stu_id=(SELECT id FROM student WHERE name= ‘李四‘ );
10.用连接的方式查询所有学生的信息和考试信息
SELECT student.id,name,sex,birth,department,address,c_name,grade FROM student,score WHERE student.id=score.stu_id;
11.计算每个学生的总成绩
SELECT student.id,name,SUM(grade) FROM student,score WHERE student.id=score.stu_id GROUP BY id; (两个表都有id，要注意冲突)
12.计算每个考试科目的平均成绩
SELECT c_name,AVG(grade) FROM score GROUP BY c_name;
13.查询计算机成绩低于95的学生信息
SELECT * FROM student WHERE id IN (SELECT stu_id FROM score WHERE c_name="计算机" and grade<95);
14.查询同时参加计算机和英语考试的学生的信息
SELECT * FROM student WHERE id =ANY ( SELECT stu_id FROM score WHERE stu_id IN ( SELECT stu_id FROM score WHERE c_name= ‘计算机‘) AND c_name= ‘英语‘ );（=ANY 与子查询IN相同）
SELECT a.* FROM student a ,score b ,score c WHERE a.id=b.stu_id AND b.c_name=‘计算机‘ AND a.id=c.stu_id AND c.c_name=‘英语‘;
15.将计算机考试成绩按从高到低进行排序
SELECT stu_id, grade FROM score WHERE c_name= ‘计算机‘ ORDER BY grade DESC;
16.从student表和score表中查询出学生的学号，然后合并查询结果
SELECT id FROM student UNION SELECT stu_id FROM score;
17.查询都是湖南的学生的姓名、年龄、院系和考试科目及成绩
SELECT student.id, name,sex,birth,department, address, c_name,grade FROM student, score WHERE address LIKE ‘湖南%‘ AND student.id=score.stu_id;
18.查询姓张或者姓王的同学的姓名、院系和考试科目及成绩
SELECT student.id, name,sex,birth,department, address, c_name,grade FROM student, score WHERE (name LIKE ‘张%‘ OR name LIKE ‘王%‘) AND student.id=score.stu_id ;
19.查询student表中学生的学号、姓名、年龄、院系和籍贯并且按照年龄从小到大的顺序排列。
select student.id,name,2017-birth,department,address from student ORDER BY 2017-birth；
20.统计超过2人考试的科目
select c_name ,count(*) from score group by c_name having count(*)>2