打印列表中没有括号的单行

I have a list in Python e.g.

我有一个Python列表，例如

names = ["Sam", "Peter", "James", "Julian", "Ann"]

I want to print the array in a single line without the normal " []

我想在没有正常“[]的单行中打印数组

names = ["Sam", "Peter", "James", "Julian", "Ann"]
print (names)

Will give the output as;

将输出作为;

["Sam", "Peter", "James", "Julian", "Ann"]

That is not the format I want instead I want it to be like this;

这不是我想要的格式，而是我希望它像这样;

Sam, Peter, James, Julian, Ann

Note: It must be in a single row.

注意：它必须在一行中。

8 个解决方案

#1

128

print ', '.join(names)

This, like it sounds, just takes all the elements of the list and joins them with ', '.

这听起来像只需要列表中的所有元素并将它们与'，'连接起来。

#2

Here is a simple one.

这是一个简单的。

names = ["Sam", "Peter", "James", "Julian", "Ann"]
print(*names)

the star unpacks the list and return every element in the list.

星形解包列表并返回列表中的每个元素。

#3

General solution, works on arrays of non-strings:

一般解决方案，适用于非字符串数组：

>>> print str(names)[1:-1]
'Sam', 'Peter', 'James', 'Julian', 'Ann'

#4

If the input array is Integer type then you need to first convert array into string type array and then use join method for joining with , or space whatever you want. e.g:

如果输入数组是Integer类型，那么您需要先将数组转换为字符串类型数组，然后使用join方法连接或空格您想要的任何内容。例如：

>>> arr = [1, 2, 4, 3]
>>> print(", " . join(arr))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: sequence item 0: expected string, int found
>>> sarr = [str(a) for a in arr]
>>> print(", " . join(sarr))
1, 2, 4, 3
>>>

Direct using of join which will join the integer and string will throw error as show above.

直接使用将连接整数和字符串的连接将抛出错误，如上所示。

#5

This is what you need

这就是你需要的

", ".join(names)

#6

There are two answers , First is use 'sep' setting

有两个答案，第一个是使用'sep'设置

>>> print(*names, sep = ', ')

The other is below

另一个在下面

>>> print(', '.join(names))

#7

You need to loop through the list and use end=" "to keep it on one line

您需要遍历列表并使用end =“”将其保持在一行

names = ["Sam", "Peter", "James", "Julian", "Ann"]
    index=0
    for name in names:
        print(names[index], end=", ")
        index += 1

#8

I don't know if this is efficient as others but simple logic always works:

我不知道这是否有效，但简单的逻辑始终有效：

import sys
name = ["Sam", "Peter", "James", "Julian", "Ann"]
for i in range(0, len(names)):
    sys.stdout.write(names[i])
    if i != len(names)-1:
        sys.stdout.write(", ")

Output:

输出：

Sam, Peter, James, Julian, Ann

山姆，彼得，詹姆斯，朱利安，安

#1

128

print ', '.join(names)