I am programming in Objective-C for iOS. I would like to parse an object of type NSString into a scalar of type BOOL.
我在用Objective-C为iOS编程。我想把NSString类型的对象解析成BOOL类型的标量。
I have a value, and I know that it will either be @"YES" or @"NO", but that YES (or) NO value is NSString and I just want to change NSString into BOOL.
我有一个值,我知道它可以是@"YES"或@"NO",但是YES(或)没有值是NSString,我只想把NSString改为BOOL。
How can I do that?
我怎么做呢?
Please answer me if you know.
如果你知道,请回答我。
Thanks for reading.
感谢你的阅读。
5 个解决方案
#1
143
I think it's this:
我认为它是这样的:
BOOL boolValue = [myString boolValue];
#2
22
You should probably use NSString
's -boolValue
. To quote the documentation directly:
你应该使用NSString的-boolValue。直接引用文件:
[Returns t]he Boolean value of the receiver’s text. Returns YES on encountering one of "Y", "y", "T", "t", or a digit 1-9—the method ignores any trailing characters. Returns NO if the receiver doesn’t begin with a valid decimal text representation of a number.
返回接收者文本的布尔值。当遇到“Y”、“Y”、“T”、“T”或数字1-9时返回YES,该方法将忽略任何尾随字符。如果接收者不以有效的十进制数字表示开头,则返回NO。
That would seem to match your input cases.
这似乎与你的输入情况相符。
#3
2
if ([string isEqualToString: @"YES"])
foo();
else
bar();
#4
0
This would probably best be solved with a conditional, for example:
这个问题最好是有条件的解决,例如:
if ([myString isEqualToString:@"YES"])
myBool = YES;
else if ([myString isEqualToString:@"NO"])
myBool = NO;
Hope this helped you, good luck with your programming.
希望这对您有所帮助,祝您编程顺利。
#5
0
This property should also return true if string is 'true' that's why i think extension is needed...
如果字符串是“true”,那么这个属性也应该返回true,这就是为什么我认为需要扩展……
extension NSString{
var boolValueExtended: Bool {
get{
return boolValue ||
self.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet()).uppercaseString == "TRUE"
}
}
}
}
#1
143
I think it's this:
我认为它是这样的:
BOOL boolValue = [myString boolValue];
#2
22
You should probably use NSString
's -boolValue
. To quote the documentation directly:
你应该使用NSString的-boolValue。直接引用文件:
[Returns t]he Boolean value of the receiver’s text. Returns YES on encountering one of "Y", "y", "T", "t", or a digit 1-9—the method ignores any trailing characters. Returns NO if the receiver doesn’t begin with a valid decimal text representation of a number.
返回接收者文本的布尔值。当遇到“Y”、“Y”、“T”、“T”或数字1-9时返回YES,该方法将忽略任何尾随字符。如果接收者不以有效的十进制数字表示开头,则返回NO。
That would seem to match your input cases.
这似乎与你的输入情况相符。
#3
2
if ([string isEqualToString: @"YES"])
foo();
else
bar();
#4
0
This would probably best be solved with a conditional, for example:
这个问题最好是有条件的解决,例如:
if ([myString isEqualToString:@"YES"])
myBool = YES;
else if ([myString isEqualToString:@"NO"])
myBool = NO;
Hope this helped you, good luck with your programming.
希望这对您有所帮助,祝您编程顺利。
#5
0
This property should also return true if string is 'true' that's why i think extension is needed...
如果字符串是“true”,那么这个属性也应该返回true,这就是为什么我认为需要扩展……
extension NSString{
var boolValueExtended: Bool {
get{
return boolValue ||
self.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet()).uppercaseString == "TRUE"
}
}
}
}