I have a C
function of this signature:
我有这个签名的C函数:
int fileopen(const char *fname, int flags)
int fileopen(const char *fname, int flags)
In Linux system, I want to pass the fname
from Python using ctypes
so I use ctypes.c_char_p("file1.dat")
as the following:
在Linux系统中,我想使用ctype从Python中传递fname,所以我使用ctypes.c_char_p(“file1.dat”)作为如下内容:
import ctypes as ctypes
dll_name = "IO/pyaio.so"
dllabspath = os.path.dirname(os.path.abspath(__file__)) + os.path.sep + dll_name
pyaio = ctypes.CDLL(dllabspath)
fd_w = pyaio.fileopen(ctypes.c_char_p("file1.dat"), 1)
But I get this error:
但是我得到了这个错误:
Traceback (most recent call last):
File "test.py", line 21, in <module>
fd_w = pyaio.fileopen(ctypes.c_char_p("file1.dat"), 1) # 0 read, 1 write
TypeError: bytes or integer address expected instead of str instance
I don't know another way to pass the string"file1.dat"
than using ctypes.c_char_p
. How to solve this problem?
我不知道另一种传递字符串“file1”的方法。比使用ctypes.c_char_p dat”。如何解决这个问题?
Thank you
谢谢你!
1 个解决方案
#1
2
Change "file1.dat"
to b"file1.dat"
(which is the same you would get with 'file1.dat'.encode('ascii')
).
改变“file1。dat file1“b”。dat(与“file1.dat”.encode(“ascii”)相同。
#1
2
Change "file1.dat"
to b"file1.dat"
(which is the same you would get with 'file1.dat'.encode('ascii')
).
改变“file1。dat file1“b”。dat(与“file1.dat”.encode(“ascii”)相同。