如何在C中为结构数组正确分配内存?

时间:2021-05-10 19:56:41

This is the first time I'm using structs as I am still relatively new to C. When I try to input values for 3 structs the program crashes, but it works fine for 1 and 2. I think I may not actually be allocating enough memory. Is this the correct way to allocate memory for an array of structs?

这是我第一次使用结构,因为我仍然是C的相对新手。当我尝试输入3个结构的值时,程序崩溃,但它适用于1和2.我想我可能实际上没有足够的分配记忆。这是为结构数组分配内存的正确方法吗?

#include <stdio.h>
#include <stdlib.h>

#define MIN_SIZE 0
#define MAX_SIZE 100
#define MAX_MONTH_STR 9

//Define a struct data type
typedef struct
{
    char* month;
    int day;
    int year;
}date;

//Method to allocate memory for a list of date structures
date* allocateStruct(int size)
{
    //Declaration of variables
    date *array;
    int i;

    //Allocate memory for rows (to store 'size' many pointers to 'date' struct data type)
    array = malloc(size*sizeof(date*));

    //For-loop to allocate memory for columns (to store 'size' many integers, and initialize them to zero)
    for (i=0; i<size; i++)
    {
        array[i].month = calloc(MAX_MONTH_STR,sizeof(char));
        array[i].day = calloc(1,sizeof(int));
        array[i].year = calloc(1,sizeof(int));
    }

    return array;
}

//Method to free memory allocated
//TO DO. . .

int main()
{
    //Declaration of variables
    int n;
    date* date_list;
    int i, j, k; //used in loops

    //Read input
    do
    {
        //printf("Enter number of dates you want to enter (between 1 and 10000):\n");
        scanf("%d", &n);
    }while(n<MIN_SIZE || n>MAX_SIZE);

    //ALLOCATE MEMORY
    date_list = allocateStruct(n);


    //For-loop to store values in 'date_list'
    for (i=0; i<n; i++)
    {
        //printf("Enter the date (month day year) in the following format: text number number");
        scanf("%s", date_list[i].month);
        scanf("%d", &date_list[i].day);
        scanf("%d", &date_list[i].year); //need & ?
    }

//--------> crashes here if 3 dates are input, ok for 1 and 2

    //Test print
    for (i=0; i<n; i++)
    {
        //printf("Enter the date (month day year) in the following format: text number number");
        printf("%s ", date_list[i].month);
        printf("%d ", date_list[i].day);
        printf("%d\n", date_list[i].year); //need & ?
    }

    return 0;
}

1 个解决方案

#1


2  

You are trying to allocate a array with the size of the pointer to the date struct instead of the actual size of the date struct.

您正在尝试分配一个数组,其指针的大小指向日期结构,而不是日期结构的实际大小。

Change date* to date:

将日期*更改为日期:

array = malloc(size*sizeof(date));

array = malloc(size * sizeof(date));

Furthermore you don't need to allocate the day and year variables, because the malloc allocates them for you.

此外,您不需要分配日期和年份变量,因为malloc会为您分配它们。

for (i=0; i<size; i++)
{
     array[i].month = calloc(MAX_MONTH_STR,sizeof(char));
     array[i].day = 0;
     array[i].year = 0;
}

#1


2  

You are trying to allocate a array with the size of the pointer to the date struct instead of the actual size of the date struct.

您正在尝试分配一个数组,其指针的大小指向日期结构,而不是日期结构的实际大小。

Change date* to date:

将日期*更改为日期:

array = malloc(size*sizeof(date));

array = malloc(size * sizeof(date));

Furthermore you don't need to allocate the day and year variables, because the malloc allocates them for you.

此外,您不需要分配日期和年份变量,因为malloc会为您分配它们。

for (i=0; i<size; i++)
{
     array[i].month = calloc(MAX_MONTH_STR,sizeof(char));
     array[i].day = 0;
     array[i].year = 0;
}