I am not quite clear on how to allocate memory to a struct pointer that contains a dynamic array field. for example, I have the following struct:
我不太清楚如何将内存分配给包含动态数组字段的结构指针。例如，我有以下结构：
typedef struct log_file {
char *name;
int updatesize;
int numupdates;
int *users; /* dynamic array of integers */
} log_data;
When I created a pointer of log_data using: log_data *log_ptr = malloc(sizeof(log_data));
当我使用以下命令创建log_data指针时：log_data * log_ptr = malloc（sizeof（log_data））;
How do I allocate enough memory for the dynamic array users in the struct?
如何为结构中的动态数组用户分配足够的内存？
1 个解决方案
#1
1
How about:
怎么样：
log_ptr->users = malloc(sizeof(int)*numOfUsers);
Or if you want to keep it independent of the type of *users:
或者，如果您想保持它独立于*用户的类型：
log_ptr->users = malloc(sizeof(*log_ptr->users)*numOfUsers);
#1
1
How about:
怎么样：
log_ptr->users = malloc(sizeof(int)*numOfUsers);
Or if you want to keep it independent of the type of *users:
或者，如果您想保持它独立于*用户的类型：
log_ptr->users = malloc(sizeof(*log_ptr->users)*numOfUsers);