I have the following query:
我有以下查询:
$this->db
->select('SQL_CALC_FOUND_ROWS null as rows
,table1.*
,table2.*
,table3.*', FALSE)
->from('table1')
->where('table1.column1', $user_id)
->join('table2', 'table2.column2 = table1.column2')
->join('table3', 'table3.column2 = table1.column2')
->group_by('table1.column2')
->order_by('table1.column2', 'DESC');
$query = $this->db->get();
The problem is, there may not be a row in table 3 and if there is not, I would still like to return a result with the remainder of the query data. Please could someone advise how to achieve this?
问题是,表3中可能没有行,如果没有,我仍然希望返回带有剩余查询数据的结果。有人可以建议如何实现这一目标吗?
2 个解决方案
#1
1
you should do a left join on table3
你应该在table3上做一个左连接
#2
0
Use left join and also use group_by to get exact records:
使用左连接并使用group_by获取准确的记录:
$this->db->join('login_ranknames AS t4', 't4.id = t1.rank', 'left');
$this->db->group_by('t4.id');
#1
1
you should do a left join on table3
你应该在table3上做一个左连接
#2
0
Use left join and also use group_by to get exact records:
使用左连接并使用group_by获取准确的记录:
$this->db->join('login_ranknames AS t4', 't4.id = t1.rank', 'left');
$this->db->group_by('t4.id');