Please note where I have the NSLOG. All it is displaying in the log is the first three items in the nameSection. After some testing, I discovered it is displaying how many keys there are because if I add a key to the plist, it will log a fourth item in log.
请注意我在哪里有NSLOG。它在日志中显示的只是nameSection中的前三项。经过一些测试后,我发现它显示了有多少个键,因为如果我向plist添加一个键,它将在日志中记录第四个项目。
nameSection should be an array of the strings that make up the key array in the plist file.
nameSection应该是组成plist文件中的键数组的字符串数组。
the plist file has 3 dictionaries, each with several arrays of strings. The code picks the dictionary I am working with correctly, then should use the array names as sections in the table and the strings en each array as what to display in each cell.
plist文件有3个字典,每个字典都有几个字符串数组。代码选择我正在使用的字典,然后应该使用数组名作为表中的部分,并将每个数组中的字符串用作每个单元格中显示的内容。
so if the dictionary i am working with has 3 arrays, NSLOG will display 3 strings from the first array:
因此,如果我正在使用的字典有3个数组,NSLOG将显示第一个数组中的3个字符串:
2010-05-01 17:03:26.957 Checklists[63926:207] string0 2010-05-01 17:03:26.960 Checklists[63926:207] string1 2010-05-01 17:03:26.962 Checklists[63926:207] string2
2010-05-01 17:03:26.957检查表[63926:207] string0 2010-05-01 17:03:26.960检查表[63926:207] string1 2010-05-01 17:03:26.962检查表[63926:207]字符串2
then stop with: 2010-05-01 17:03:26.963 Checklists[63926:207] * Terminating app due to uncaught exception 'NSRangeException', reason: '* -[NSCFArray objectAtIndex:]: index (3) beyond bounds (3)'
然后停止:2010-05-01 17:03:26.963清单[63926:207] *由于未捕获的异常'NSRangeException'终止应用程序,原因:'* - [NSCFArray objectAtIndex:]:索引(3)超出界限(3) )”
if i added an array to the dictionary, it log 4 items instead of 3.
如果我在字典中添加了一个数组,它会记录4个项而不是3个。
I hope this explanation makes sense...
我希望这个解释有意义......
-(NSInteger)numberOfSectionsInTableView:(UITableView *)tableView{
return [keys count];
}
-(NSInteger)tableView:(UITableView *)tableView
numberOfRowsInSection:(NSInteger) section {
NSString *key = [keys objectAtIndex:section];
NSArray *nameSection = [names objectForKey:key];
return [nameSection count];
}
-(UITableViewCell *)tableView:(UITableView *)tableView
cellForRowAtIndexPath:(NSIndexPath *)indexPath {
NSUInteger section = [indexPath section];
NSString *key = [keys objectAtIndex: section];
NSArray *nameSection = [names objectForKey:key];
static NSString *SectionsTableIdentifier = @"SectionsTableIdentifier";
static NSString *ChecklistCellIdentifier = @"ChecklistCellIdentifier ";
ChecklistCell *cell = (ChecklistCell *)[tableView
dequeueReusableCellWithIdentifier: SectionsTableIdentifier];
if (cell == nil)
{
NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"ChecklistCell"
owner:self options:nil];
for (id oneObject in nib)
if ([oneObject isKindOfClass:[ChecklistCell class]])
cell = (ChecklistCell *)oneObject;
}
NSUInteger row = [indexPath row];
NSDictionary *rowData = [self.keys objectAtIndex:row];
NSString *tempString = [[NSString alloc]initWithFormat:@"%@",[nameSection objectAtIndex:row]];
NSLog(@"%@",tempString);
cell.colorLabel.text = [tempArray objectAtIndex:0];
cell.nameLabel.text = [tempArray objectAtIndex:1];
return cell;
return cell;
}
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
UITableViewCell *cell = [tableView cellForRowAtIndexPath:indexPath];
if (cell.accessoryType == UITableViewCellAccessoryNone) {
cell.accessoryType = UITableViewCellAccessoryCheckmark;
}
else if (cell.accessoryType == UITableViewCellAccessoryCheckmark) {
cell.accessoryType = UITableViewCellAccessoryNone;
}
[tableView deselectRowAtIndexPath:indexPath animated:NO];
}
-(NSString *)tableView:(UITableView *)tableView
titleForHeaderInSection:(NSInteger)section{
NSString *key = [keys objectAtIndex:section];
return key;
}
2 个解决方案
#1
0
In tableView:cellForRowAtIndexPath: you're doing this:
在tableView:cellForRowAtIndexPath中:你这样做:
NSDictionary *rowData = [self.keys objectAtIndex:row];
This has at least two problems:
这至少有两个问题:
-
Based on your implementation of numberOfSectionsInTableView:, it seems you have one key per section. This code is looking for a key for every row in the current indexPath.section.
根据您对numberOfSectionsInTableView:的实现,您似乎每个部分都有一个密钥。此代码正在查找当前indexPath.section中每一行的键。
-
In tableView:numberOfRowsInSection:, -[keys objectAtIndex:] returns an NSString. Here you're treating it as an NSDictionary.
在tableView:numberOfRowsInSection:中, - [keys objectAtIndex:]返回一个NSString。在这里,您将其视为NSDictionary。
#2
0
Found the problem. It was this (pointless) line of code. Removed it and it worked fine.
发现了问题。这是(无意义的)代码行。删除它,它工作正常。
NSDictionary *rowData = [self.keys objectAtIndex:row];
NSDictionary * rowData = [self.keys objectAtIndex:row];
#1
0
In tableView:cellForRowAtIndexPath: you're doing this:
在tableView:cellForRowAtIndexPath中:你这样做:
NSDictionary *rowData = [self.keys objectAtIndex:row];
This has at least two problems:
这至少有两个问题:
-
Based on your implementation of numberOfSectionsInTableView:, it seems you have one key per section. This code is looking for a key for every row in the current indexPath.section.
根据您对numberOfSectionsInTableView:的实现,您似乎每个部分都有一个密钥。此代码正在查找当前indexPath.section中每一行的键。
-
In tableView:numberOfRowsInSection:, -[keys objectAtIndex:] returns an NSString. Here you're treating it as an NSDictionary.
在tableView:numberOfRowsInSection:中, - [keys objectAtIndex:]返回一个NSString。在这里,您将其视为NSDictionary。
#2
0
Found the problem. It was this (pointless) line of code. Removed it and it worked fine.
发现了问题。这是(无意义的)代码行。删除它,它工作正常。
NSDictionary *rowData = [self.keys objectAtIndex:row];
NSDictionary * rowData = [self.keys objectAtIndex:row];