I have a piece of code where I need to figure out if a given type implements IEnumerable<T>
(I don't care about the T)
我有一段代码,我需要弄清楚一个给定的类型是否实现了IEnumerable
I've tried (t:System.Type
in case you wonder)
我试着(t:系统。类型,以防你怀疑)
let interfaces = t.GetInterfaces()
let enumerbale =
interfaces.Any(fun t ->
t.GetGenericTypeDefinition() = typeof<IEnumerable<>>
)
however that won't compile (the compile doesn't like the <>). I then tried
但是,这不会编译(编译不喜欢<>)。然后我试着
let interfaces = t.GetInterfaces()
let enumerbale =
interfaces.Any(fun t ->
t.GetGenericTypeDefinition() = typeof<IEnumerable<'a>>
)
but get's a warning that 'a is constraint to obj. I Don't want to figure out if IEnumerable<obj>
is implemented but IEnumerabl<>
.
但是得到一个警告,a是对obj的约束。我不想算出IEnumerable
Any one know's the solution and btw feel free to comment on the code above as well.
任何一个人都知道解决方案,顺便也可以对上面的代码进行评论。
3 个解决方案
#1
49
This should work:
这应该工作:
typedefof<System.IEnumerable<_>>
EDIT
编辑
As Tomas notes, there's nothing special about the _
wildcard here; F# infers that the type obj
is the most general applicable type in this context, so this is the same as using typedefof<System.IEnumerable<obj>>
. In some cases the way this works can be a bit of a hindrance, though. For instance, if you define an interface type I<'a when 'a :> I<'a>> = interface end
, then you can't use typedefof<I<_>>
, because I<obj>
doesn't satisfy the generic constraint and F# can't infer another more appropriate type. This can happen even without recursive constraints (e.g. type I<'a when 'a : struct and 'a :> System.ICloneable> = interface end
. This is in contrast to C#'s approach, which works perfectly fine in the analogous cases.
正如Tomas所指出的,这里的_wildcard没什么特别的;在这个上下文中,类型obj是最通用的类型,所以这和使用typedef
As to your code itself, I think you'll want to make some other changes, too, such as ensuring that the interface is generic before calling GetGenericTypeDefinition
. Here's how I'd write the test function:
至于代码本身,我认为您还需要做一些其他的更改,比如在调用GetGenericTypeDefinition之前确保接口是通用的。下面是我如何编写测试函数:
(fun t -> t.IsGenericType && (t.GetGenericTypeDefinition() = typedefof<_ seq>))
#2
17
As far as I know, F# doesn't have any equivalent to C#'s typeof(IEnumerable<>)
. This is because, this is a special syntax supported explicitly by C#. In F#, typeof
is a normal function and the type argument needs to be a fully specified type. You can get a generic type definition programatically like this:
据我所知,f#没有与c#的typeof(IEnumerable<>)相对应。这是因为,这是c#显式支持的特殊语法。在f#中,typeof是一个正常的函数,类型参数需要是一个完全指定的类型。你可以像这样得到一个泛型类型定义:
let t = typeof<IEnumerable<obj>>
let genericT = t.GetGenericTypeDefinition()
The problem with your solution with IEnumerable<'a>
is that the F# compiler still needs to find some concrete type to use (as generic type definition isn't a valid type). If the type inference deduces that the type parameter isn't restricted in any way, it uses default type, which is obj
.
使用IEnumerable<'a> '的解决方案的问题是,f#编译器仍然需要找到一些具体类型(作为泛型类型定义不是有效类型)。如果类型推断推断类型参数不受任何限制,则使用默认类型obj。
EDIT I didn't know about typedefof<IEnumerable<_>>
, that is very useful! Anyway, note that the underscore doesn't have any special meaning here - the actual type argument is still IEnumerable<obj>
, but the typedefof
function calls GetGenericTypeDefinition
behind the scene.
编辑我不知道
#3
5
I would be remiss not to point out that this question is one of many whose answers are found in
我不应该指出,这个问题是许多人的答案之一。
What does this C# code look like in F#?
这个c#代码在f#中是什么样子?
#1
49
This should work:
这应该工作:
typedefof<System.IEnumerable<_>>
EDIT
编辑
As Tomas notes, there's nothing special about the _
wildcard here; F# infers that the type obj
is the most general applicable type in this context, so this is the same as using typedefof<System.IEnumerable<obj>>
. In some cases the way this works can be a bit of a hindrance, though. For instance, if you define an interface type I<'a when 'a :> I<'a>> = interface end
, then you can't use typedefof<I<_>>
, because I<obj>
doesn't satisfy the generic constraint and F# can't infer another more appropriate type. This can happen even without recursive constraints (e.g. type I<'a when 'a : struct and 'a :> System.ICloneable> = interface end
. This is in contrast to C#'s approach, which works perfectly fine in the analogous cases.
正如Tomas所指出的,这里的_wildcard没什么特别的;在这个上下文中,类型obj是最通用的类型,所以这和使用typedef
As to your code itself, I think you'll want to make some other changes, too, such as ensuring that the interface is generic before calling GetGenericTypeDefinition
. Here's how I'd write the test function:
至于代码本身,我认为您还需要做一些其他的更改,比如在调用GetGenericTypeDefinition之前确保接口是通用的。下面是我如何编写测试函数:
(fun t -> t.IsGenericType && (t.GetGenericTypeDefinition() = typedefof<_ seq>))
#2
17
As far as I know, F# doesn't have any equivalent to C#'s typeof(IEnumerable<>)
. This is because, this is a special syntax supported explicitly by C#. In F#, typeof
is a normal function and the type argument needs to be a fully specified type. You can get a generic type definition programatically like this:
据我所知,f#没有与c#的typeof(IEnumerable<>)相对应。这是因为,这是c#显式支持的特殊语法。在f#中,typeof是一个正常的函数,类型参数需要是一个完全指定的类型。你可以像这样得到一个泛型类型定义:
let t = typeof<IEnumerable<obj>>
let genericT = t.GetGenericTypeDefinition()
The problem with your solution with IEnumerable<'a>
is that the F# compiler still needs to find some concrete type to use (as generic type definition isn't a valid type). If the type inference deduces that the type parameter isn't restricted in any way, it uses default type, which is obj
.
使用IEnumerable<'a> '的解决方案的问题是,f#编译器仍然需要找到一些具体类型(作为泛型类型定义不是有效类型)。如果类型推断推断类型参数不受任何限制,则使用默认类型obj。
EDIT I didn't know about typedefof<IEnumerable<_>>
, that is very useful! Anyway, note that the underscore doesn't have any special meaning here - the actual type argument is still IEnumerable<obj>
, but the typedefof
function calls GetGenericTypeDefinition
behind the scene.
编辑我不知道
#3
5
I would be remiss not to point out that this question is one of many whose answers are found in
我不应该指出,这个问题是许多人的答案之一。
What does this C# code look like in F#?
这个c#代码在f#中是什么样子?