In my recurive function to zip a whole folders i have this piece of code glob($path. '/*') that give me all files and subfolders matching my $path.
在我的recurive函数中压缩整个文件夹我有这段代码glob($ path。'/ *')给我所有文件和子文件夹匹配我的$ path。
Here I read that with glob I can get even hidden files ".filename" with glob('{,.}*', GLOB_BRACE) How to merge in one expression my needs? I tried glob('{/,.}*', GLOB_BRACE) but only give me the files I tried glob('{/,.,}*', GLOB_BRACE) but I get crazy results
在这里,我用glob读取,我甚至可以使用glob('{,。} *',GLOB_BRACE)获取隐藏文件“.filename”如何合并我需要的一个表达式?我尝试了glob('{/,。}'',GLOB_BRACE),但只给了我试过的文件glob('{/,。,}}',GLOB_BRACE但是我得到了疯狂的结果
I already filteres . and ..
我已经过滤了。和..
How to merge
如何合并
glob($dir . '/*')
and
和
glob('{,.}*', GLOB_BRACE)
5 个解决方案
#1
8
To get all folders/files (even the hidden ones):
获取所有文件夹/文件(甚至是隐藏的文件夹/文件):
$result = glob($path . '{,.}[!.,!..]*',GLOB_MARK|GLOB_BRACE);
This will prevent listing "." or ".." in the result.
这将阻止列出“。”或结果中的“..”。
#2
6
Have you tried this?
你试过这个吗?
glob($path. '/{,.}*', GLOB_BRACE);
#3
1
The glob()
method returns an array. So if you want to merge two different glob
results...
glob()方法返回一个数组。所以如果你想合并两个不同的glob结果......
$merged = array_merge(glob($dir . '/*'), glob('{,.}*', GLOB_BRACE));
#4
0
Probably you've found already the solution, but in case you were looking for a way that gives you the files and directories, recursively and taking care of hidden files, this was what I got:
可能你已经找到了解决方案,但是如果你正在寻找一种方法来提供文件和目录,递归并处理隐藏文件,这就是我得到的:
function rglob($pattern, $flags = 0) {
$files = glob($pattern, $flags);
foreach (glob(dirname($pattern).'/*', GLOB_ONLYDIR|GLOB_NOSORT) as $dir) {
$files = array_merge($files, $this->rglob($dir.'/'.basename($pattern), $flags));
}
return $files;
}
#5
0
I am answering here in case anyone else is looking as this appears high on Google.
我在这里回答,以防其他人在看,因为这在谷歌看起来很高。
Solution 1 - glob only
解决方案1 - 仅限glob
This uses a glob that is tailored to skip '.' and '..' special directories. It matches anything that:
这使用了一个专门用于跳过'。'的glob。和'..'特殊目录。它匹配任何:
- isn't hidden with a '.'
- 没有隐藏'。'
- is hidden with a '.' but is followed a non '.' character
- 隐藏着'。'但是遵循非''。字符
- starts with '..' but has at least one character after it
- 以'..'开头,但后面至少有一个字符
$globbed = glob("{*,.[!.]*,..?*}", GLOB_BRACE);
var_dump($globbed);
Solution 2 - globignore
解决方案2 - globignore
This is a function to mimic the behaviour of globignore in bash.
这是一个模仿bash中globignore行为的函数。
function globignore(array $ignore, $glob, $glob_flags = 0)
{
$globbed = glob($glob, $glob_flags);
return array_filter($globbed, function ($f) use ($ignore)
{
$base = basename($f);
foreach($ignore as $i)
{
if ($i == $base) return false;
}
return true;
});
}
$globbed = globignore(['.','..'], "{*,.*}", GLOB_BRACE);
var_dump($globbed);
They appear to execute in almost exactly the same time on my system. Solution 1 requires less code but solution 2 is easier to include more terms to ignore.
它们似乎在我的系统上几乎完全相同的时间执行。解决方案1需要更少的代码,但解决方案2更容易包含更多要忽略的术语。
#1
8
To get all folders/files (even the hidden ones):
获取所有文件夹/文件(甚至是隐藏的文件夹/文件):
$result = glob($path . '{,.}[!.,!..]*',GLOB_MARK|GLOB_BRACE);
This will prevent listing "." or ".." in the result.
这将阻止列出“。”或结果中的“..”。
#2
6
Have you tried this?
你试过这个吗?
glob($path. '/{,.}*', GLOB_BRACE);
#3
1
The glob()
method returns an array. So if you want to merge two different glob
results...
glob()方法返回一个数组。所以如果你想合并两个不同的glob结果......
$merged = array_merge(glob($dir . '/*'), glob('{,.}*', GLOB_BRACE));
#4
0
Probably you've found already the solution, but in case you were looking for a way that gives you the files and directories, recursively and taking care of hidden files, this was what I got:
可能你已经找到了解决方案,但是如果你正在寻找一种方法来提供文件和目录,递归并处理隐藏文件,这就是我得到的:
function rglob($pattern, $flags = 0) {
$files = glob($pattern, $flags);
foreach (glob(dirname($pattern).'/*', GLOB_ONLYDIR|GLOB_NOSORT) as $dir) {
$files = array_merge($files, $this->rglob($dir.'/'.basename($pattern), $flags));
}
return $files;
}
#5
0
I am answering here in case anyone else is looking as this appears high on Google.
我在这里回答,以防其他人在看,因为这在谷歌看起来很高。
Solution 1 - glob only
解决方案1 - 仅限glob
This uses a glob that is tailored to skip '.' and '..' special directories. It matches anything that:
这使用了一个专门用于跳过'。'的glob。和'..'特殊目录。它匹配任何:
- isn't hidden with a '.'
- 没有隐藏'。'
- is hidden with a '.' but is followed a non '.' character
- 隐藏着'。'但是遵循非''。字符
- starts with '..' but has at least one character after it
- 以'..'开头,但后面至少有一个字符
$globbed = glob("{*,.[!.]*,..?*}", GLOB_BRACE);
var_dump($globbed);
Solution 2 - globignore
解决方案2 - globignore
This is a function to mimic the behaviour of globignore in bash.
这是一个模仿bash中globignore行为的函数。
function globignore(array $ignore, $glob, $glob_flags = 0)
{
$globbed = glob($glob, $glob_flags);
return array_filter($globbed, function ($f) use ($ignore)
{
$base = basename($f);
foreach($ignore as $i)
{
if ($i == $base) return false;
}
return true;
});
}
$globbed = globignore(['.','..'], "{*,.*}", GLOB_BRACE);
var_dump($globbed);
They appear to execute in almost exactly the same time on my system. Solution 1 requires less code but solution 2 is easier to include more terms to ignore.
它们似乎在我的系统上几乎完全相同的时间执行。解决方案1需要更少的代码,但解决方案2更容易包含更多要忽略的术语。