如何检查字符串中包含ruby中的特殊字符

How to check whether a string contains special character in ruby. If I get regular expression also it is fine.

如何检查字符串是否包含ruby中的特殊字符。如果我得到正则表达式也没关系。

Please let me know

请告诉我

6 个解决方案

#1

special = "?<>',?[]}{=-)(*&^%$#`~{}"
regex = /[#{special.gsub(/./){|char| "\\#{char}"}}]/

You can then use the regex to test if a string contains the special character:

然后，您可以使用正则表达式来测试字符串是否包含特殊字符：

if some_string =~ regex

This looks a bit complicated: what's going on in this bit

这看起来有点复杂：这一点发生了什么

special.gsub(/./){|char| "\\#{char}"

is to turn this

是转此

"?<>',?[]}{=-)(*&^%$#`~{}"

into this:

进入这个：

"\\?\\<\\>\\'\\,\\?\\[\\]\\}\\{\\=\\-\\)\\(\\*\\&\\^\\%\\$\\#\\`\\~\\{\\}"

Which is every character in special, escaped with a \ (which itself is escaped in the string, ie \\ not \). This is then used to build a regex like this:

哪个是特殊的字符，用\ _进行转义（它本身在字符串中转义，即\\不是\）。然后用它来构建这样的正则表达式：

/[<every character in special, escaped>]/

#2

Use str.include?.

使用str.include？。

Returns true if str contains the given string or character.

如果str包含给定的字符串或字符，则返回true。

"hello".include? "lo"   #=> true
"hello".include? "ol"   #=> false
"hello".include? ?h     #=> true

#3

"foobar".include?('a')
# => true

#4

Why not use inverse of [:alnum:] posix.

为什么不使用[：alnum：] posix的倒数。

Here [:alnum:] includes all 0-9, a-z, A-Z.

这里[：alnum：]包括全0-9，a-z，A-Z。

#5

How about this command in Ruby 2.0.0 and above?

在Ruby 2.0.0及更高版本中，这个命令怎么样？

def check_for_a_special_charachter(string)   
  /\W/ === string
end

Therefore, with:

因此，有：

!"He@llo"[/\W/].nil?  => True

!"Hello"[/\W/].nil?   => False

#6

"Hel@lo".index( /[^[:alnum:]]/ )

This will return nil in case you do not have any special character and hence eaiest way I think.

如果你没有任何特殊的角色，那么这将返回零，因此我认为是最简单的方式。

#1

special = "?<>',?[]}{=-)(*&^%$#`~{}"
regex = /[#{special.gsub(/./){|char| "\\#{char}"}}]/