I have an object of the following form (simplified test case below)
我有一个以下形式的对象(下面的简化测试用例)
var test = {
shirts: {
sizes: ['large', 'medium']
,colors:['red', 'blue']
}
, trousers: {
type: ['formal', 'casual']
, pattern: ['plaid', 'stripes']
}
};
I want to generate a cartesian product of the properties so that the output is an array of the following form:
我想生成属性的笛卡尔积,以便输出是以下形式的数组:
// desired output
[ {shirts:{sizes:'large', color:'red'}, trousers:{type:'formal', pattern:'plaid'}}
,{shirts:{sizes:'large', color:'red'}, trousers:{type:'formal', pattern:'stripes'}}
,{shirts:{sizes:'large', color:'red'}, trousers:{type:'casual', pattern:'plaid'}}
, {shirts:{sizes:'large', color:'red'}, trousers:{type:'casual', pattern:'stripes'}}
,{shirts:{sizes:'large', color:'blue'}, trousers:{type:'formal', pattern:'plaid'}}
..... and so on ]
How can I achieve this? I worked up the following code (based on a modification of code for cartesian product of array from another SO post) but I seem to be tying myself in knots trying to get this to work.
我怎样才能做到这一点?我编写了以下代码(基于对来自另一个SO帖子的数组的笛卡尔积的代码的修改)但我似乎将自己绑在试图使其工作的结。
function myCartesianProduct(input, current) {
if (!input) { return []; }
var head = input[Object.keys(input)[0]];
var tail = objSlice(input);
var output = [];
for (var key in head) {
for (var i = 0; i < head[key].length; i++) {
var newCurrent = copy(current);
newCurrent[key] = head[key][i];
if (Object.keys(tail).length) { //if tail.length
var productOfTail =
myCartesianProduct(tail, newCurrent);
output = output.concat(productOfTail);
} else {
output.push(newCurrent);
}
}
}
return output;
}
function objSlice(obj) {
var slicedObj = angular.copy(obj); // copy object using angularJs copy method
delete slicedObj[Object.keys(slicedObj)[0]]; //delete the first key
return slicedObj;
};
function copy(obj) {
var res = {};
for (var p in obj) res[p] = obj[p];
return res;
}
console.log(myCartesianProduct(test));
Thanks in advance for your help with this!
在此先感谢您的帮助!
1 个解决方案
#1
7
Ok, let's start with a function that generates a product of given arrays:
好吧,让我们从一个生成给定数组产品的函数开始:
function product(args) {
if(!args.length)
return [[]];
var prod = product(args.slice(1)), r = [];
args[0].forEach(function(x) {
prod.forEach(function(p) {
r.push([x].concat(p));
});
});
return r;
}
The next one uses product
to convert something like {a:[1,2], b:[3,4]}
into [{a:1,b:3},{a:1,b:4},{a:2,b:3},{a:2,b:4}]
:
下一个使用产品将{a:[1,2],b:[3,4]}之类的内容转换为[{a:1,b:3},{a:1,b:4},{a :2,b:3},{A:2,b:4}]:
function objectProduct(obj) {
var keys = Object.keys(obj),
values = keys.map(function(x) { return obj[x] });
return product(values).map(function(p) {
var e = {};
keys.forEach(function(k, n) { e[k] = p[n] });
return e;
});
}
For your test data, you have to apply it twice:
对于测试数据,您必须应用两次:
var result = {};
Object.keys(test).forEach(function(k) {
result[k] = objectProduct(test[k])
});
result = objectProduct(result);
This gives you the output you wanted.
这为您提供了所需的输出。
#1
7
Ok, let's start with a function that generates a product of given arrays:
好吧,让我们从一个生成给定数组产品的函数开始:
function product(args) {
if(!args.length)
return [[]];
var prod = product(args.slice(1)), r = [];
args[0].forEach(function(x) {
prod.forEach(function(p) {
r.push([x].concat(p));
});
});
return r;
}
The next one uses product
to convert something like {a:[1,2], b:[3,4]}
into [{a:1,b:3},{a:1,b:4},{a:2,b:3},{a:2,b:4}]
:
下一个使用产品将{a:[1,2],b:[3,4]}之类的内容转换为[{a:1,b:3},{a:1,b:4},{a :2,b:3},{A:2,b:4}]:
function objectProduct(obj) {
var keys = Object.keys(obj),
values = keys.map(function(x) { return obj[x] });
return product(values).map(function(p) {
var e = {};
keys.forEach(function(k, n) { e[k] = p[n] });
return e;
});
}
For your test data, you have to apply it twice:
对于测试数据,您必须应用两次:
var result = {};
Object.keys(test).forEach(function(k) {
result[k] = objectProduct(test[k])
});
result = objectProduct(result);
This gives you the output you wanted.
这为您提供了所需的输出。