如何在PHP（stdClass对象）中回显JSON？

This is a simple JSON but it cannot access an item. I send the that JSON to get.php and there just print_r the JSON and in parsing JSON response is problem.

这是一个简单的JSON,但它无法访问项目。我将该JSON发送到get.php,只有print_r JSON和解析JSON响应是有问题的。

My code:

$url = "http://localhost/get.php";    
    $data = array(
        'item1'      => 'value1',
        'item2'      => 'value2',
        'item3'      => 'value3'
    );


$content = json_encode($data);

$curl = curl_init($url);
curl_setopt($curl, CURLOPT_HEADER, false);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER,
array("Content-type: application/json"));
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $content);

$json_response = curl_exec($curl);
$status = curl_getinfo($curl, CURLINFO_HTTP_CODE);

if ( $status == 201 ) {
die("Error: call to URL $url failed with status $status, response $json_response, curl_error " . curl_error($curl) . ", curl_errno " curl_errno($curl));
}


curl_close($curl);
$response = json_decode($json_response, false);
$result=json_encode($json_response);
$data=json_decode($result);

How can I echo item 1 or 2 ?

我该如何回应第1项或第2项?

This is get.php

这是get.php

if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
  $data = json_decode(file_get_contents("php://input"));
  print_r($data);
}

4 个解决方案

#1

Since get.php uses print_r(), it's not returning JSON. It needs to use json_encode().

由于get.php使用print_r(),因此它不返回JSON。它需要使用json_encode()。

if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
  $data = json_decode(file_get_contents("php://input"));
  echo json_encode($data);
}

Then your curl script can decode it properly.

然后你的curl脚本可以正确解码它。

$response = json_decode($json_response, false);
echo 'Item1 = ' . $response->item1 . '<br>';
echo 'Item2 = ' . $response->item2 . '<br>';
echo 'Item3 = ' . $response->item3;

#2

You don't need set second param in json_decode function for getting stdClass.

您不需要在json_decode函数中设置第二个参数来获取stdClass。

$data = array(
    'item1' => 'value1',
    'item2' => 'value2',
    'item3' => 'value3'
);
$json=json_encode($data);
$result=json_decode($json);
echo $result->item1;
echo $result->item2;
echo $result->item3;

Or you can work with array

或者你可以使用数组

$json=json_encode($data);
$result=json_decode($json, true);
echo $result['item1'];
echo $result['item2'];
echo $result['item3'];

#3

use json_encode() to encode the data , then print the json

使用json_encode()对数据进行编码,然后打印json

  $data = json_decode(file_get_contents("php://input"));
  echo json_encode($data);

#4

-1

curl_close($curl);
$result = json_decode($jsonResponse, true);
echo $result['item1']; //Echo item 1.

#1