mysql中TIMESTAMPDIFF案例详解

时间：2022-08-27 10:33:11

1.  Syntax

TIMESTAMPDIFF(unit,begin,end); 根据单位返回时间差,对于传入的begin和end不需要相同的数据结构,可以存在一个为Date一个DateTime

2. Unit

支持的单位有

  • MICROSECOND
  • SECOND
  • MINUTE
  • HOUR
  • DAY
  • WEEK
  • MONTH
  • QUARTER
  • YEAR

3. Example

下面这个例子是对于TIMESTAMPDIFF最基本的用法，

  • 3.1 求 2017-01-01 - 2017-02-01 之间有几个月
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SELECT TIMESTAMPDIFF(MONTH, '2017-01-01', '2017-02-01') as  result;
 
+--------+
| result |
+--------+
| 1 |
+--------+
1 row in set (0.00 sec)
  • 3.2 求 2017-01-01 - 2017-02-01 之间有几天
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SELECT TIMESTAMPDIFF(DAY, '2017-01-01', '2017-02-01') as  result;
 
+--------+
| result |
+--------+
| 31 |
+--------+
1 row in set (0.00 sec)
  •  3.3 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:00 之间有几分钟
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SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:00') result;
 
+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)
  •  3.4 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:33 之间有几分钟
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SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;
 
+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)
  •  3.5 对于DAY， MINUTE进行计算DIFF时，会直接将相对应的DAY，MINUTE相减

mysql中TIMESTAMPDIFF案例详解

  • 3.6 对于 SECOND 会怎样计算呢
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SELECT TIMESTAMPDIFF(SECOND, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;
 
55 * 60 + 33 = 3333
+--------+
| result |
+--------+
|   3333 |
+--------+
1 row in set (0.00 sec)
  • 3.7 如何求数据库中两个date字段的diff
    • 3.7.1  建表
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      CREATE TABLE demo (id INT AUTO_INCREMENT PRIMARY KEY, start_time DATE NOT NULL, end_time DATE NOT NULL);
      Query OK, 0 rows affected (0.10 sec)
    • 3.7.2  添加数据
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      INSERT INTO demo(start_time, end_time)
      VALUES('1983-01-01', '1990-01-01'),
      ('1983-01-01', '1989-06-06'),
      ('1983-01-01', '1985-03-02'),
      ('1983-01-01', '1992-05-05'),
      ('1983-01-01 11:12:11', '1995-12-01');
    • 3.7.3 直接query数据
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      select * from demo;
      +----+------------+------------+
      | id | start_time | end_time |
      +----+------------+------------+
      | 1 | 1983-01-01 | 1990-01-01 |
      | 2 | 1983-01-01 | 1989-06-06 |
      | 3 | 1983-01-01 | 1985-03-02 |
      | 4 | 1983-01-01 | 1992-05-05 |
      | 5 | 1983-01-01 | 1995-12-01 |
      +----+------------+------------+
      5 rows in set (0.00 sec)
    • 3.7.4 计算duration
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      select *, TIMESTAMPDIFF(YEAR, start_time, end_time) as duration from demo;
       
      +----+------------+------------+----------+
      | id | start_time | end_time | duration |
      +----+------------+------------+----------+
      | 1 | 1983-01-01 | 1990-01-01 | 7 |
      | 2 | 1983-01-01 | 1989-06-06 | 6 |
      | 3 | 1983-01-01 | 1985-03-02 | 2 |
      | 4 | 1983-01-01 | 1992-05-05 | 9 |
      | 5 | 1983-01-01 | 1995-12-01 | 12 |
      +----+------------+------------+----------+
      5 rows in set (0.00 sec)
    • 3.7.5 其他应用
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      select *, if(TIMESTAMPDIFF(YEAR, end_time, CURRENT_TIMESTAMP())< 26 ,'< 26','>= 26') as result from demo;
       
      +----+------------+------------+--------+
      | id | start_time | end_time | result |
      +----+------------+------------+--------+
      | 1 | 1983-01-01 | 1990-01-01 | >= 26 |
      | 2 | 1983-01-01 | 1989-06-06 | >= 26 |
      | 3 | 1983-01-01 | 1985-03-02 | >= 26 |
      | 4 | 1983-01-01 | 1992-05-05 | < 26 |
      | 5 | 1983-01-01 | 1995-12-01 | < 26 |
      +----+------------+------------+--------+
      5 rows in set (0.00 sec)

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原文链接：https://blog.csdn.net/baiyaoliang7445/article/details/102218767

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