如何反序列化另一个列出的项目中存在的xml文件列出的项目

I have an auto generated xml file with the following format.

我有一个自动生成的xml文件，格式如下。

<?xml version="1.0"?>
<School>
  <Classes numberOfFields="5">
    <Class name="10" dataType="double">
        <Section value="A"/>
        <Section value="B"/>
        <Section value="C"/>
    </Class>
    <Class dataType="double"/>
    <Class dataType="double"/>
    <Class dataType="double"/>
    <Class dataType="double"/>
  </Classes>
</School>

I deserialize using "XmlDeserializer" as follows

我使用“XmlDeserializer”反序列化如下

School schoolResult = (School)xmlSerializer.Deserialize(stream);

XmlRootElement contains a collection of "Class" under "Classes" tag and further each "Class" would contain Collection of "Section".

XmlRootElement在“Classes”标记下包含“Class”的集合，并且每个“Class”将包含“Section”的集合。

And in C#, I have declared like this to deserialize "Classes" into a List of classes.

在C＃中，我已声明这样将“类”反序列化为类列表。

[XmlArray("Classes")]
[XmlArrayItem("Class", typeof(Class))]
public List<Class> Classes {};

Now to further deserialize Class into List of Sections, I have added the code as below.

现在为了进一步将Class反序列化为Sections List，我添加了如下代码。

[XmlArray("Class")]
[XmlArrayItem(ElementName="Section")]
public List<Section> ClassSections {};

My problem is I couldn't get the List of Sections values properly. Because I have "Class" as a class name in the first part and in second part I have mentioned same "Class" as Array element. So could any one tell how can I properly Deserialize my "School" object using "XmlSerializer" to get all the values properly.

我的问题是我无法正确获取Sections列表值。因为我在第一部分和第二部分中有“Class”作为类名，所以我提到了与Array元素相同的“Class”。那么任何人都可以告诉我如何使用“XmlSerializer”正确地反序列化我的“School”对象以正确获取所有值。

Note: I cannot have a Array root tag like "Sections" under "Class". Because my xml document is auto generated. I cannot specify my own format.

注意：我不能在“类”下面有像“部分”这样的数组根标记。因为我的xml文档是自动生成的。我无法指定自己的格式。

Thanks...

谢谢...

2 个解决方案

#1

    static void Main(string[] args)
    {
        var xml ="<?xml version=\"1.0\"?><School><Classes numberOfFields=\"5\"><Class name=\"10\" dataType=\"double\"><Section value=\"A\"/><Section value=\"B\"/><Section value=\"C\"/></Class><Class dataType=\"double\"/><Class dataType=\"double\"/><Class dataType=\"double\"/><Class dataType=\"double\"/></Classes></School>";
        School result;
        var serializer = new XmlSerializer(typeof(School));
        var xmlDoc = new XmlDocument();
        xmlDoc.LoadXml(xml);
        using (var reader = new XmlNodeReader(xmlDoc))
        {
            result = (School)serializer.Deserialize(reader);
        }
    }


public class School
{
    [XmlArray("Classes")]
    [XmlArrayItem("Class")]
    public List<Class> Classes { get; set; }
}

public class Class
{
    [XmlElement("Section")]
    public List<Section> ClassSections { get; set; }
}

public class Section
{
    [XmlAttribute("value")]
    public string Value { get; set; }
}

#2

try this :

尝试这个 ：

    public class School
{
    [XmlAttribute]
    public int numberOfFields { get; set; }

    [XmlArray("Classes")]
    [XmlArrayItem("Class", typeof(Class))]
    public List<Class> Classes { get; set; }

}


public class Class
{
    [XmlAttribute]
    public string name { get; set; }
    [XmlAttribute]
    public string dataType { get; set; }


    [XmlElement("Section")]
    public List<Section> ClassSections { get; set; }

}

public class Section
{
    [XmlAttribute]
    public string value { get; set; }
}

* EDIT #1 **

*编辑＃1 **

--------------- Update Structure due to NumberOfFields is not readed ----------------

---------------由于NumberOfFields导致的更新结构未被重新加载----------------

in my opinion it's not correct structure, but when u said it's an auto generated XML file, i think it simplest way to read it.

在我看来，它不是正确的结构，但是当你说它是一个自动生成的XML文件时，我认为这是最简单的阅读方式。

    public class School
{

    [XmlElement("Classes")]
    public List<ArrayClass> Classes { get; set; }

}

public class ArrayClass
{
    [XmlAttribute]
    public int numberOfFields { get; set; }

    [XmlElement("Class")]
    public List<Class> Class { get; set; }

}