通过Python中的套接字发送一个文件。

I'm trying to make a program in Python that implements sockets, each client sends a PDF file and the server receives it and the title is changed to "file_number.pdf" (i.e.: file_1.pdf). The problem presented is that only a client can send a file successfully. When a second client tries to send the program does crash. What am I doing wrong and how can I solve my code to allow N clients (with N <20) to connect to the server and transfer files?

我尝试在Python中创建一个实现套接字的程序，每个客户机发送一个PDF文件，服务器接收它，然后将标题改为“file_number”。pdf”(即。:file_1.pdf)。出现的问题是只有客户机才能成功发送文件。当第二个客户机试图发送程序时，它会崩溃。我做错了什么，我该如何解决我的代码让N个客户端(有N <20)连接到服务器和传输文件?

Here's the server code:

这里的服务器代码:

import socket
import sys
s = socket.socket()
s.bind(("localhost",9999))
s.listen(10) # Acepta hasta 10 conexiones entrantes.
sc, address = s.accept()

print address
i=1
f = open('file_'+ str(i)+".pdf",'wb') # Open in binary
i=i+1
while (True):

    # Recibimos y escribimos en el fichero
    l = sc.recv(1024)
    while (l):
        f.write(l)
        l = sc.recv(1024)
f.close()

sc.close()
s.close()

Here's the client code:

客户端代码:

import socket
import sys

s = socket.socket()
s.connect(("localhost",9999))
f = open ("libroR.pdf", "rb")
l = f.read(1024)
while (l):
    s.send(l)
    l = f.read(1024)
s.close()

To simplify my code I always use a book with file name "libroR.pdf", but in the full code it is chosen by a graphical user interface.

为了简化我的代码，我总是使用一个名为“libroR”的书。但在完整的代码中，它是由图形用户界面选择的。

3 个解决方案

#1

You must put all the code from sc, address = s.accept() upto sc.close() into another loop or the server simply terminates after receiving the first file. It doesn't crash, the script is just finished.

您必须将所有的代码从sc, address = .accept() upto sc.close()到另一个循环，或者在收到第一个文件后，服务器将终止。它不会崩溃，脚本刚刚完成。

[EDIT] Here is the revised code:

[编辑]这是修改后的代码:

import socket
import sys
s = socket.socket()
s.bind(("localhost",9999))
s.listen(10) # Acepta hasta 10 conexiones entrantes.

while True:
    sc, address = s.accept()

    print address
    i=1
    f = open('file_'+ str(i)+".pdf",'wb') #open in binary
    i=i+1
    while (True):       
    # recibimos y escribimos en el fichero
        l = sc.recv(1024)
        while (l):
                f.write(l)
                l = sc.recv(1024)
    f.close()


    sc.close()

s.close()

Note that s.listen(10) means "set maximum accept rate to 10 connections", not "stop after 10 connections".

注意。listen(10)的意思是“将最大接受率设置为10个连接”，而不是“在10个连接后停止”。

#2

Your code is getting stuck in the second while loop.

你的代码在循环中被卡住了。

See:

看到的:

import socket
import sys
s = socket.socket()
s.bind(("localhost",9999))
s.listen(10)

i=1

while True:
    sc, address = s.accept()

    print address

    f = open('file_'+str(i)+".pdf",'wb') #open in binary
    i=i+1
    print(i)
    l = 1
    while(l):
        l = sc.recv(1024)
        while (l):
            f.write(l)
            l = sc.recv(1024)
        f.close()


    sc.close()

s.close()

#3

You are closing the server socket (s in your code) after handling the first client connection. Thus only one client is ever handled by your server. Make a loop around accept and reading from the sc.

在处理第一个客户端连接后，您正在关闭服务器套接字(在您的代码中)。因此，服务器只处理一个客户机。从sc中对接收和读取进行循环。

#1