When I click on tr
without any filter, my function array.splice()
works. Indexes in the array are in the correct order, so the array.splice()
works.
当我没有任何过滤器点击tr时,我的函数array.splice()工作。数组中的索引按正确的顺序排列,因此array.splice()可以工作。
When the filter is enable, Indexes in the array are not updated and still in the same order. So array.splice()
removes the wrong item.
当启用筛选器时,数组中的索引不会被更新,并且仍然保持相同的顺序。因此,array.splice()删除了错误的项。
<span ng-click="orderP0 = 'statut_name'; reversePO=!reversePO">order</span>
<tr ng-repeat="project in projects | orderBy : orderPO : reverse track by $index" ng-click="remove($event,$index,projects)">
<span class="label" ng-bind="project.statut_name"></span>
</tr>
$scope.remove = function($event,index,array){
array.splice(index,1);
};
How to update index in the array ? Or How to removes the right item ?
如何更新数组中的索引?或者如何删除正确的项目?
2 个解决方案
#1
8
The simplest solution would be to change your remove function to take in the project instead of the index.
最简单的解决方案是更改您的remove函数,而不是索引。
$scope.remove = function(project){
for(var i = $scope.projects.length - 1; i >= 0; i--){
if($scope.projects[i].statut_name == project.statut_name){
$scope.projects.splice(i,1);
}
}
}
Example Plunker: http://plnkr.co/edit/51SNVMQjG3dsmpYI5RyY?p=preview
例子恰好:http://plnkr.co/edit/51SNVMQjG3dsmpYI5RyY?p=preview
#2
21
It's easier to splice you projects in the actual position of the element in the array using indexOf.
使用indexOf更容易将项目拼接到数组中元素的实际位置。
$scope.remove = function(project){
$scope.projects.splice($scope.projects.indexOf(project),1);
}
This way you need to pass to the remove function only the current project.
通过这种方式,您只需要将删除函数传递给当前项目。
<tr ng-repeat="project in projects | orderBy : orderPO : reverse track by $index" ng-click="remove(project)">
<span class="label" ng-bind="project.statut_name"></span>
</tr>
#1
8
The simplest solution would be to change your remove function to take in the project instead of the index.
最简单的解决方案是更改您的remove函数,而不是索引。
$scope.remove = function(project){
for(var i = $scope.projects.length - 1; i >= 0; i--){
if($scope.projects[i].statut_name == project.statut_name){
$scope.projects.splice(i,1);
}
}
}
Example Plunker: http://plnkr.co/edit/51SNVMQjG3dsmpYI5RyY?p=preview
例子恰好:http://plnkr.co/edit/51SNVMQjG3dsmpYI5RyY?p=preview
#2
21
It's easier to splice you projects in the actual position of the element in the array using indexOf.
使用indexOf更容易将项目拼接到数组中元素的实际位置。
$scope.remove = function(project){
$scope.projects.splice($scope.projects.indexOf(project),1);
}
This way you need to pass to the remove function only the current project.
通过这种方式,您只需要将删除函数传递给当前项目。
<tr ng-repeat="project in projects | orderBy : orderPO : reverse track by $index" ng-click="remove(project)">
<span class="label" ng-bind="project.statut_name"></span>
</tr>