从php生成关联数组json

Expected JSON structure:

预期的JSON结构:

{"music" : [ 
    { 
        "title" : "Jazz in Paris",
        "album" : "Jazz & Blues"
    },
    { 
        "title" : "Jazz in Paris",
        "album" : "Jazz & Blues"
    }
    .......
    .......
]}

Current JSON:

{"music":{"title":"Origin of evil","album":"devotional"}}

Code:

$sub = array();
foreach ($this->data as  $value)
{
    $sub['title'] = $value['title'];
    $sub['album'] = "devotional";
}
$audio = array('music'=>$sub);
echo json_encode($audio);

4 个解决方案

#1

Just create an array outside of the foreach and then append the subarray into main array using [].

只需在foreach之外创建一个数组,然后使用[]将子数组附加到主数组中。

Like this,

$audio=array();
$audio["music"]=array();
foreach ($this->data as  $value)
        {
            $sub = array();
            $sub['title'] = $value['title'];
            $sub['album'] = "devotional";
            $audio["music"][]=$sub;
        }

echo json_encode($audio);

This will create an array of music and each sub array as a object of it.

这将创建一个音乐数组,并将每个子数组作为其对象。

#2

Change a bit in your existing code-

改变现有代码中的一点 -

Just add extra array to the $sub as array($sub).

只需将额外数组添加到$ sub as array($ sub)。

$audio = array('music'=>array($sub));

#3

Try with this

试试这个

    $sub = array();
    foreach ($this->data as  $value)
    {
        $temp['title'] = $value['title'];
        $temp['album'] = "devotional";
        array_push($sub, $temp);
    }
    $audio = array('music'=>$sub);
    echo json_encode($audio);

#4

You need to wrap things in another array. just change echo json_encode(array($audio));

你需要将东西包装在另一个数组中。只需更改echo json_encode(array($ audio));

$sub = array();
foreach ($this->data as  $value)
{
    $sub['title'] = $value['title'];
    $sub['album'] = "devotional";
}
$audio = array('music'=>array($sub)); // just add array so whole things are wrap in another array.

echo json_encode($audio);

#1