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- Find object by id in an array of JavaScript objects 28 answers
- 在JavaScript对象数组中按id查找对象28个答案
I have JSON objects that have several properties such as an id and name. I store them in a JavaScript array and then based on a dropdownlist I want to retrieve the object from the JavaScript array based on its id.
我有一些JSON对象,它们具有一些属性,比如id和名称。我将它们存储在一个JavaScript数组中,然后基于下拉列表,根据对象的id从JavaScript数组中检索对象。
Suppose an object has id and name, how do I select them from my array variable?
假设一个对象有id和名称,如何从数组变量中选择它们?
var ObjectsList = data;
var id = $("#DropDownList > option:selected").attr("value");
ObjectsList["id=" + id];
1 个解决方案
#1
58
Since you already have jQuery, you could use $.grep
:
既然已经有了jQuery,可以使用$.grep:
Finds the elements of an array which satisfy a filter function. The original array is not affected.
查找满足筛选函数的数组元素。原始数组不受影响。
So something like this:
所以这样的:
var matches = $.grep(ObjectsList, function(e) { return e.id == id });
that will leave you with an array of matching entries from ObjectsList
in the array matches
. The above assumes that ObjectsList
has a structure like this:
这将为您在数组匹配中保留来自ObjectsList的匹配项数组。上面假设ObjectsList有这样的结构:
[
{ id: ... },
{ id: ... },
...
]
If you know that there is only one match or if you only want the first then you could do it this way:
如果你知道只有一个匹配,或者你只想要第一个,你可以这样做:
for(var i = 0, m = null; i < ObjectsList.length; ++i) {
if(ObjectsList[i].id != wanted_id)
continue;
m = a[i];
break;
}
// m is now either null or the one you want
There are a lot of variations on the for
loop approach and a lot of people will wag a finger at me because they think continue
is a bad word; if you don't like continue
then you could do it this way:
for循环方法有很多变体很多人会对我摇手指因为他们认为continue是一个坏词;如果你不喜欢继续,你可以这样做:
for(var i = 0, m = null; i < ObjectsList.length; ++i) {
if(ObjectsList[i].id == wanted_id) {
m = ObjectsList[i];
break;
}
}
#1
58
Since you already have jQuery, you could use $.grep
:
既然已经有了jQuery,可以使用$.grep:
Finds the elements of an array which satisfy a filter function. The original array is not affected.
查找满足筛选函数的数组元素。原始数组不受影响。
So something like this:
所以这样的:
var matches = $.grep(ObjectsList, function(e) { return e.id == id });
that will leave you with an array of matching entries from ObjectsList
in the array matches
. The above assumes that ObjectsList
has a structure like this:
这将为您在数组匹配中保留来自ObjectsList的匹配项数组。上面假设ObjectsList有这样的结构:
[
{ id: ... },
{ id: ... },
...
]
If you know that there is only one match or if you only want the first then you could do it this way:
如果你知道只有一个匹配,或者你只想要第一个,你可以这样做:
for(var i = 0, m = null; i < ObjectsList.length; ++i) {
if(ObjectsList[i].id != wanted_id)
continue;
m = a[i];
break;
}
// m is now either null or the one you want
There are a lot of variations on the for
loop approach and a lot of people will wag a finger at me because they think continue
is a bad word; if you don't like continue
then you could do it this way:
for循环方法有很多变体很多人会对我摇手指因为他们认为continue是一个坏词;如果你不喜欢继续,你可以这样做:
for(var i = 0, m = null; i < ObjectsList.length; ++i) {
if(ObjectsList[i].id == wanted_id) {
m = ObjectsList[i];
break;
}
}