Javascript - 解析JSON，包括int作为Object

After several test and search, I can't find a way to navigate after parsing a JSON; here is the post-parsing result :

经过多次测试和搜索,我在解析JSON之后找不到导航的方法;这是解析后的结果:

    Object {documentation: "https://geocoder.opencagedata.com/api", licenses: Array[2], rate: Object, results: Array[1], status: Object…}

documentation : "https://geocoder.opencagedata.com/api" licenses : Array[2] rate : Object results : Array[1] 0 : Object annotations : Object components : Object building : "C" city : "Bordeaux" country : "France" country_code : "fr" county : "Bordeaux" postcode : "33000" road : "Quai de Bacalan" state : "Aquitaine" suburb : "Bordeaux Maritime"

文档:“https://geocoder.opencagedata.com/api”licenses:Array [2] rate:Object results:Array [1] 0:Object annotations:Object components:Object building:“C”city:“Bordeaux”country :“法国”country_code:“fr”县:“波尔多”邮政编码:“33000”道路:“Quai de Bacalan”州:“阿基坦”郊区:“波尔多海事”

For example I can get the value of the response with the following code :

例如,我可以使用以下代码获取响应的值:

var locname = response.status.code;

But in the case there is a int as Object, like this :

但是在这种情况下有一个int作为Object,如下所示:

var locname = response.results.0.formatted;

I have the following error :

我有以下错误:

Uncaught SyntaxError: Unexpected number

未捕获的SyntaxError:意外的数字

I try to escape the character, putting quote, etc but I couldn't find any solution.

我试图逃避角色,引用等等,但我找不到任何解决方案。

2 个解决方案

#1

Since results is an array you must use the following syntax:

由于结果是数组,因此必须使用以下语法:

var locname = response.results[0].formatted;

Instead of

var locname = response.results.0.formatted;

#2

in javascript, an object is also accessible as array, so for example, you have an object like this:

在javascript中,一个对象也可以作为数组访问,例如,你有一个像这样的对象:

var obj = {name: 'Hans Yulian', age: 21, message: 'Handsome'};
obj[0] = 'This is an number index';
obj['message'] = 'Too Handsome';

all the key is accepted as long as they aren't something that contain special characters (-+=! etc) and not started with number. in any case you have the field that don't satisfy this exception, then you have to access it in array-way. you can assign the value the same way as array, and also to get the content of that field.

所有密钥都被接受,只要它们不是包含特殊字符的东西( - + =!等)而不是以数字开头。在任何情况下,您都有不满足此异常的字段,那么您必须以数组方式访问它。您可以使用与数组相同的方式分配值,也可以获取该字段的内容。

in case you need to access something like

如果你需要访问类似的东西

var locname = response.results.0.formatted;

Then the thing that you need is

然后你需要的是

var locname = response.results[0].formatted;

you can try make a html file with this content

你可以试着用这个内容制作一个html文件

<script>
    var obj = {name: 'Hans Yulian', age: 21, message: 'Handsome'};
    obj[0] = 'This is an number index';
    obj['message'] = 'Too Handsome';
    obj[1] = {};
    obj[1].name = 'Handsome';
    obj.handsome = [];
    obj.handsome[0] = {};
    obj.handsome[0].hansyulian = 'So Handsome';

    console.log(obj);
    console.log(obj[1].name);
    console.log(obj.handsome[0].hansyulian);
</script>

and try see the console(right click, inspect element, select console for google chrome) to understand what happens there

并尝试查看控制台(右键单击,检查元素,选择谷歌浏览器的控制台)以了解那里发生的事情

#1