复杂对象的JSON解析

Given below is the type of JSON response ,

下面给出JSON响应的类型，

{
  "?xml":{
    "@version":"1.0",
    "@encoding":"iso-8859-1"
  },
  "xmlreport":{
    "@title":"ABC: TEST Most Saved2",
    "@dates":"Week of May 19,2013",
    "columns":{
      "column":[
        {
          "@name":"Page",
          "@type":"dimension",
          "#text":"Page"
        },
        {
          "@name":"Events",
          "@type":"metric",
          "@hastotals":"true",
          "#text":"Events"
        }
      ]
    },
    "rows":{
      "row":[
        {
          "@rownum":"1",
          "cell":[
            {
              "@columnname":"page",
              "@csv":"\"http://www.ABC.com/profile/recipebox\"",
              "#text":"http://www.ABC.com/profile/recipebox"
            },
            {
              "@columnname":"events",
              "@percentage":"\"0.1%\"",
              "#text":"489"
            }
          ]
        },
        {
          "@rownum":"2",
          "cell":[
            {
              "@columnname":"page",
              "@csv":"\"http://www.ABC.com/recipes/peanut-butter-truffle-brownies/c5c602e4-007b-43e0-aaab-2f9aed89524c\"",
              "#text":"http://www.ABC.com/recip...c602e4-007b-43e0-aaab-2f9aed89524c"
            },
            {
              "@columnname":"events",
              "@percentage":"\"0.0%\"",
              "#text":"380"
            }
          ]
        }
      ]
    },
    "totals":{
      "pagetotals":{
        "total":{
          "@columnname":"events",
          "@value":"1820.000000",
          "#text":"1,820 (0.2%)"
        }
      },
      "reporttotals":{
        "total":{
          "@columnname":"events",
          "@value":"7838.000000",
          "#text":"7,838 (0.8%)"
        }
      },
      "timeperiodtotals":{
        "total":{
          "@columnname":"events",
          "@value":"955774.000000",
          "#text":"955,774 (100.0%)"
        }
      }
    }
  }
}

I am unable to parse the object.Could you please help me out how do I read the attributes and elements after parsing. I am using C#

我无法解析该对象。你能告诉我解析后如何读取属性和元素吗?我使用c#

{ 
     XmlDocument doc = new XmlDocument();
     doc.LoadXml(XML);

     string jsonText = JsonConvert.SerializeXmlNode(doc);
     //var result = Newtonsoft.Json.JsonConvert.DeserializeXmlNode(jsonText, "xmlreport");
     var results = JsonConvert.DeserializeObject<dynamic>(jsonText);

     JToken token = JObject.Parse(jsonText);
     var report = token["xmlreport"];
}

3 个解决方案

#1

My understanding of the question is you've got some Xml and you need to send out json. Couple of points before we get to the code:

我对这个问题的理解是，您有一些Xml，需要发送json。在我们开始讲代码之前有几点:

1) Don't convert xml to json directly as it causes issues

1)不要直接将xml转换成json，因为它会引起问题

2) Parse the xml to objects at your end and then work out the format to return; decoupling what comes in and goes out will allow for one of the interfaces to change in the future without impacting the other as you can tweak the mapping

2)解析xml到您端对象，然后计算返回的格式;解耦输入和输出将允许其中一个接口在未来更改，而不会影响另一个接口，因为您可以调整映射

So, onto the code ...

所以，在代码上……

Essentially parse the xml to objects to allow for further processing and then push out as json.

本质上，将xml解析为对象，以便进行进一步处理，然后以json的形式推出。

class Program
{
    private static string starting =
        "<xmlreport title=\"ABC: TEST Most Saved2\" dates=\"Week of May 19,2013\"><columns><column name=\"Page\" type=\"dimension\">Page</column><column name=\"Events\" type=\"metric\" hastotals=\"true\">Events</column></columns><rows><row rownum=\"1\"><cell columnname=\"page\" csv=\"http://www.ABC.com/profile/recipebox\">http://www.ABC.com/profile/recipebox</cell><cell columnname=\"events\" percentage=\"0.1%\">489</cell></row><row rownum=\"2\"><cell columnname=\"page\" csv=\"http://www.ABC.com/recipes/peanut-butter-truffle-brownies/c5c602e4-007b-43e0-aaab-2f9aed89524c\">http://www.ABC.com/recipes/peanut-butter-truffle-brownies/c5c602e4-007b-43e0-aaab-2f9aed89524c</cell><cell columnname=\"events\" percentage=\"0.0%\">380</cell></row></rows><totals><pagetotals><total columnname=\"events\" value=\"1820.00000\">1,820 (0.2%)</total></pagetotals><reporttotals><total columnname=\"events\" value=\"7838.000000\">7,838 (0.8%)</total></reporttotals><timeperiodtotals><total columnname=\"events\" value=\"955774.000000\">955,774 (100.0%)</total></timeperiodtotals></totals></xmlreport>";


    static void Main(string[] args)
    {
        // parse from xml to objects
        StringReader reader = new StringReader(starting);
        XmlSerializer xmlSerializer = new XmlSerializer(typeof(XmlReport));
        var xmlreport = (XmlReport)xmlSerializer.Deserialize(reader);

        // todo: do some process mapping ...

        // parse out as json
        var json = JsonConvert.SerializeObject(xmlreport);

        Console.WriteLine(json);
        Console.ReadLine();
    }
}

[Serializable]
[XmlRoot(ElementName = "xmlreport")]
public class XmlReport
{
    [XmlAttribute(AttributeName = "title")]
    public string Title { get; set; }
    [XmlAttribute(AttributeName = "dates")]
    public string Dates { get; set; }

    [XmlArray(ElementName = "columns")]
    [XmlArrayItem(typeof(Column), ElementName = "column")]
    public Collection<Column> Columns { get; set; }
}

[Serializable]
public class Column
{
    [XmlAttribute(AttributeName = "name")]
    public string Name { get; set; }
    [XmlAttribute(AttributeName = "type")]
    public string Type { get; set; }
}

I've tried to parse the json to the original xml to begin with so appologies if I've not interpreted it properly. I've not done the entire structure but I hope the example above gives you an idea of how to do the rest.

我尝试将json解析为原始的xml，如果没有正确地解释它，就以appologies开头。我还没有完成整个结构，但我希望上面的示例能让您了解如何完成其余部分。

Hope this helps.

希望这个有帮助。

#2

One way of doing this is by getting the actual Data Structure of that JSON object that you have there.

一种方法是获取JSON对象的实际数据结构。

Then create classes representing that data structure (if you can get a complete response -- having all properties, you just use this site to convert that to classes).

然后创建表示该数据结构的类(如果您可以得到一个完整的响应——拥有所有属性，您只需使用该站点将其转换为类)。

After that, deserialize that JSON object into your class using different libraries available. A sample could be this one.

之后，使用可用的不同库将JSON对象反序列化到您的类中。一个样本可以是这个。

#3

Use this (JSon.NET) and a recursive function writes all keys and values to output window.

使用这个(JSon.NET)，递归函数将所有键和值写入输出窗口。

        [TestMethod]
        public void ParseMePlease()
        {


            string s = @"{""?xml"":{""@version"":""1.0"",""@encoding"":""iso-8859-1""},
                            ""xmlreport"":{""@title"":""ABC: TEST Most Saved2"",""@dates"":""Week of May 19,2013"",
                            ""columns"":{""column"":[{""@name"":""Page"",""@type"":""dimension"",""#text"":""Page""},{""@name"":""Events"",""@type"":""metric"",""@hastotals"":""true"",""#text"":""Events""}]},
                            ""rows"":
                            {""row"":[{""@rownum"":""1"",""cell"":[{""@columnname"":""page"",""@csv"":""\""http://www.ABC.com/profile/recipebox\"""",""#text"":""http://www.ABC.com/profile/recipebox""},{""@columnname"":""events"",""@percentage"":""\""0.1%\"""",""#text"":""489""}]},
                            {""@rownum"":""2"",""cell"":[{""@columnname"":""page"",""@csv"":""\""http://www.ABC.com/recipes/peanut-butter-truffle-brownies/c5c602e4-007b-43e0-aaab-2f9aed89524c\"""",""#text"":""http://www.ABC.com/recip...c602e4-007b-43e0-aaab-2f9aed89524c""},{""@columnname"":""events"",""@percentage"":""\""0.0%\"""",""#text"":""380""}]}]},
                            ""totals"":{""pagetotals"":{""total"":{""@columnname"":""events"",""@value"":""1820.000000"",""#text"":""1,820 (0.2%)""}},
                            ""reporttotals"":{""total"":{""@columnname"":""events"",""@value"":""7838.000000"",""#text"":""7,838 (0.8%)""}},
                            ""timeperiodtotals"":{""total"":{""@columnname"":""events"",""@value"":""955774.000000"",""#text"":""955,774 (100.0%)""}}}}}";         
            var result=JsonConvert.DeserializeObject<object>(s);

            Debug.WriteLine("Right Click Result on quick watch for Result Views!(On Debug)"+result.ToString() );

            JObject jobject = ((Newtonsoft.Json.Linq.JObject)result);


            PrintDetail(jobject);

        }

        public void PrintDetail(JObject node)
        {
            foreach (var item in node)
            {                    
                Debug.WriteLine("Key:" + item.Key + " Value:" + item.Value);
                if (item.Value is JObject)
                {
                    PrintDetail((JObject)item.Value);
                }
            }
        }